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I am Lyosha [343]
3 years ago
11

A fence post is 7 feet tall. A chain is attached to the top of the fence post and fastened to the ground 5 feet from the base of

the fence post. What is the length of the chain?
Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0
The length of the chain is 2 feet
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3+x=3 whats the answer its 100 points
schepotkina [342]
X is 0 so that means you answer would be 3+0=3
5 0
3 years ago
What is the approximate surface area of a cylinder with a radius of 3 inches and a height of 10 inches?
xxMikexx [17]
245in^2

Curved surface = 2pi x r x h = 2 x 3.1 x 3 x 10 = 186
2 ends = 2 x (Pi x r x r) = 2 x 3.1 x 3 x 3 = 55.8
Total area = 186 + 55.8 = 242in^2 approximately
5 0
3 years ago
The circumference of the inner circle is 44 ft. The distance between the inner circle and the outer circle is 3 ft. By how many
Citrus2011 [14]

Answer: 18.86 feet

Step-by-step explanation:

The formula for determining the circumference of a circle is expressed as

Circumference = πD

Where D represents the diameter of the circle.

The circumference of the inner circle is 44 ft. It means that

22/7 × D = 44

22D = 7 × 44 = 308

D = 308/22

D = 14 ft

The distance between the inner circle and the outer circle is 3 ft. This means that the diameter of the outer circle would be

14 + 3 + 3 = 20 ft

Circumference of the outer circle is

22/7 × 20 = 62.86 ft

The number of feet by which the circumference of outer circle is greater than the circumference of the inner circle is

62.86 - 44 = 18.86 feet

5 0
4 years ago
Solve the expression (7th grade math):<br><br> -0.8m+3-12.5m+95.36m
Lana71 [14]

Step-by-step explanation:

<u>Combine Like-Terms:</u>

-0.8m + 3 - 12.5m + 95.36m

-13.3m + 3 + 95.36m

82.06m + 3

82.06m + 3 is your simplified expression.

7 0
2 years ago
Can someone help me please
Morgarella [4.7K]

Answer:

<u>The volume of this figure is approximately 418.88 centimeters squared!</u>

Step-by-step explanation:

The volume for a right circular cone is V = (π)(r^2)(h/3)

Substituting known values is as follows:

V = (π)(r^2)(h/3)

V = (π)(4^2)(25/3)

V = (π)(16)(25/3)

<u>V ≈ 418.88 cm^3</u>

5 0
3 years ago
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