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Art [367]
2 years ago
13

The height of a cylinder is 8 centimeters. The circumference of the base of the cylinder is 14 pi. What is the measurement of th

e volume of the cylinder in cubic centimeters? Round to the nearest tenth.
Mathematics
1 answer:
timurjin [86]2 years ago
3 0

Answer:

15

Step-by-step explanation:

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se the drawing tool to form the correct answers on the provided grid. For the sequence (1, 2, 4, 8, . . .), the index starts at
Andru [333]

Answer:

See attached

Step-by-step explanation:

For each increase of 1 in the index, the function value doubles. The size of the function value rapidly exceeds the limit of any linear grid.

We've shown a few points plotted. Perhaps it will give you the idea of what you need to do.

6 0
3 years ago
The divisor of 0.004 is almost zero. What does this tell you about the quotient?
nasty-shy [4]

Answer:

  Its magnitude will be larger than 0.004.

Step-by-step explanation:

When a divisor is less than 1, the quotient will be greater than the dividend.

When the divisor is "almost zero", the quotient will be much greater than the dividend. Here, the dividend may be considered to be "almost zero", so we cannot say anything about the actual quotient except to say its magnitude will be greater than the dividend.

_____

The dividend is positive, so the quotient will have the same sign as the divisor. (Negative divisors can be "almost zero," too.)

3 0
3 years ago
Did you hear the one about the acupuncture
Alecsey [184]

The answer is "It was A Jab Well Done" You have to finish the whole sheet to get the answer

8 0
3 years ago
He length of a rectangle is three times its width. The perimeter of the rectangle is at most 112 cm.
g100num [7]
The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <= 4 \sqrt{7}
W <= \frac{4 \sqrt{7} }{3} cm
8 0
3 years ago
Read 2 more answers
A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat
LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

=200 meters

6 0
1 year ago
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