Answer:
1. annual tuition 2. $-27139 3. slope = -0.91
Step-by-step explanation:
1. An independent variable is the factor that is not determined by the model in this case the annual tuition variable (the linear regression model factor)
2. substitute $30,000 into the linear regressions equation gives:
y = -0.91(30000) + 161 = -27139
This value tells us that when the annual tuition is $30,000 the average mid-career salary of graduates is predicted to be -$27,139
3. the slope if the regression is represented by the coefficient of the factor in the linear regression model. In this case, as the factor is x or the annual tuition, and the coefficient of this variable in the given example is -0.91 which in turn is the slope of the model.
Answer:
The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0
Step-by-step explanation:
Given Trigonometrical function as :
= 2 (1 + cosec A)
Or,
= 2 (1 + cosec A)
,<u> Now, rationalizing </u>
= 2 (1 + cosec A)
Or,
= 2 ( 1 + 
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= 2 ( 
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= 2 ( 
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= 2 ( 
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= 2 ( 
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= 2 ( 
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= 2 ( 
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= 2 ( 
Or, sin A + sin² A = 2 cos A (1 + sin A)
Or, sin A + sin² A = 2 cos A + 2 cos A × sin A
Or, sin² A + sin A - 2 cos A - 2 cos A × sin A = 0
So,The trigonometrical expression is sin² A + sin A - 2 cos A - 2 cos A × sin A = 0 Answer
To find the percentage divide 10 by 100.. each chapter would make up 10% of the book.
Answer:
Part 1) The exact value of the arc length is \frac{25}{6}\pi \ in
Part 2) The approximate value of the arc length is 13.1\ in
Step-by-step explanation:
ind the circumference of the circle
The circumference of a circle is equal to
C=2\pi r
we have
r=5\ in
substitute
C=2\pi (5)
C=10\pi\ in
step 2
Find the exact value of the arc length by a central angle of 150 degrees
Remember that the circumference of a circle subtends a central angle of 360 degrees
by proportion
\frac{10\pi}{360} =\frac{x}{150}\\ \\x=10\pi *150/360\\ \\x=\frac{25}{6}\pi \ in
Find the approximate value of the arc length
To find the approximate value, assume
\pi =3.14
substitute
\frac{25}{6}(3.14)=13.1\ in