Question

Please Solve:Adding and Subtracting Polymonials

Answer 1

$Add:\\ \\ (-6-n + 2n^2) + (8 - 3n - 10n^2) =\\ \\= -6-n + 2n^2 + 8 - 3n - 10n^2 =\\ \\=2 - 4n -8n^2 \\ \\ Answer : \ C. \ \ \2 - 4n - 8n2$


$Add: \\ \\ (8x + 2y - 3z -4) + (-4x - 5y + 4z + 6) = \\ \\ =8x + 2y - 3z -4 -4x - 5y + 4z + 6=\\ \\=4 x - 3 y + z + 2 \\ \\ Answer : \ D. \ \ \ 4x - 3y + z + 2$


$Subtract \ and \ simplify: \\\\ (2p^2q - 3pq^2 + q^3) -(p^2q + q^3)=\\ \\= 2p^2q - 3pq^2 + q^3 - p^2q -q^3 = \\ \\= p^2q - 3pq^2 \\ \\ Answer : \ A. \ \ \ \ p^2q - 3pq^2$


$Subtract \ and \ simplify: \\\\ (-y^2 - 3y-5) - (-3y^2 - 7y + 4)= \\ \\= -y^2 - 3y-5+3y^2 +7y- 4 =\\ \\=2y^2+4y-9 \\ \\Answer : \ B.\ \ \ \ 2y^2 + 4y - 9$


$Subtract \ and \ simplify: \\\\ (10x^4 -2x + 7)-(6x^4 + 2x^3 -4x^2 - 1) = \\ \\ = 10x^4 -2x + 7 - 6x^4 - 2x^3 +4x^2 + 1=\\ \\=4x^4 -2x^3 +4x^2-2x + 8 \\ \\Answer : \ C. \ \ \ \4x^4 -2x^3 + 4x^2- 2x + 8$
 

Answer 2

$1)\\(-6-n + 2n^2) + (8-3n-10n^2) =2-4n-8n^2\ \ \ \Rightarrow\ \ \ Ans.\ C\\\\2)\\(8x+2y-3z-4)+(-4x-5y+4z+6)=4x-3y+z+2\ \Rightarrow\ Ans.D\\\\3)\\(2p^2q-3pq^2+q^3)-(p^2q + q^3) =p^2q-3pq^2\ \ \ \Rightarrow\ \ \ Ans.\ A\\\\4)\\ (-y^2-3y-5)-(-3y^2-7y + 4) =-y^2-3y-5+3y^2+7y - 4=\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =2y^2+4y-9\ \ \ \Rightarrow\ \ \ Ans.\ B$

$5)\\(10x^4-2x + 7)-(6x^4 + 2x^3-4x^2-1) =\\=10x^4-2x + 7-6x^4 - 2x^3+4x^2+1=\\=4x^4-2x^3+4x^2-2x+8\ \ \ \Rightarrow\ \ \ Ans.\ C$