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Vaselesa [24]
3 years ago
12

Dennis has a has 9.5 weeks to prepare for a bike tour. if he rides his bike 8.2 miles each week, how many miles will a ride befo

re the bike tour
Mathematics
1 answer:
charle [14.2K]3 years ago
3 0
He will bike 77.9 miles after 9 and a half weeks
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Help me Please Please Please Please Pleaseeeeeeee
Thepotemich [5.8K]
H = 151t - 16t²

The height of the ball when it return to the ground will be 0
0 = 151t - 16t²

The zero product property is that when two numbers are being multiplied and the product is 0, one of them must be equal to 0. Therefore, we can factorize this equation:
16t² - 151t = 0
t(16t - 151t) = 0
By the zero product property:
t = 0   or  16t - 151 = 0

So t = 0 or t = 9.44 seconds

The first solution is before he releases the ball and the second is when the ball comes back to the ground. Thus, the ball's air time is 9.44 seconds.
6 0
3 years ago
Please help solve what the picture says and explain. Thanks!
pochemuha
Guess this is how it should look like, not sure what the instructions on drawing an x through the segments mean, but hope this helps!

4 0
3 years ago
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Paha777 [63]
Answer is b because angle BPD is greater than 90 degree
7 0
4 years ago
What is the length of the missing side , x? 22, 11, x
yulyashka [42]

Answer:

33

Step-by-step explanation:

I say 33, because of the 11 times table

4 0
3 years ago
What is the length of side a?
Bad White [126]

\huge \bf༆ Answer ༄

According to given figure, The Triangle BDC is a right angled Triangle (Angle D = 90°)

So, we can apply Pythagoras theorem to find the Side a (Hypotenuse)

Now, let's solve ~

  • \sf \: BD {}^{2}   + CD {}^{2} =   BC {}^{2}

  • \sf4 {}^{2}  +  {3}^{2}  =  {a}^{2}

  • \sf16 + 9 =  {a}^{2}

  • \sf \: a {}^{2}  = 25

  • \sf \: a =  \sqrt{25}

  • \sf \: a  = 5 \: units

Therefore, Length of side a is 5 units ~

6 0
3 years ago
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