Answer:
5.0 ft-lbf
Step-by-step explanation:
The force is

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

with
and
the initial and final displacements respectively.
From the question,
and
.
Then

Evaluating the indefinite integral,

From the rules of integration,


Returning the limits,

187=190
186=190 because 18.7 and 18.6 are 187 and 186 so 8 is the tenth place. So they both equal 190
Answer:
4.8 miles
Step-by-step explanation:
have a good day!
Hehas 337 dollrs because 220:65% is one so that is it
The answer would be A, it has no solution