Answer:
0.025
Step-by-step explanation:
Rounded to the nearest thousandth
Answer:
56°
Step-by-step explanation:
<u>Since SQ bisects ∠RST, we have:</u>
- m∠RST = 2* m∠ QST = 2* m∠RSQ
<u>Therefore:</u>
- 6x - 2 = 2*(2x + 18)
- 6x - 2 = 4x + 36
- 2x = 38
- x = 19°
<u>Then</u>
For part a: you just need to find how far the vertex has been moved from the origin, or the point (0,0). As the vertex is at the point (2,-3), it has been translated right 2 horizontally and down 3 vertically.
For part b: you use the info found in part a to create the equation in the form of y=A(x-h)^2+k. In this case, A =1, so you can ignore it. The h value is the horizontal distance the vertex has been moved. Since it has been moved right 2, this part of the equation would be (x-2). I know it seems like it should be plus 2, but values in parentheses come out opposite. For the k value, find the vertical shift, which is down3, or -3.
Now that you have h and k, substitute them back into the equation.
Your final answer for part b is: y=(x-2)^2 -3.
Answer:
y = 6x + 28
Step-by-step explanation:
We are to determine the equation of a line whose slope or gradient is 6 and passes through the point (-4, 4)
The slope-intercept form of the equation of the straight line would be given by;
y = mx + c
y = 6x + c
We proceed to use the given point to determine c;'
when x = -4, y = 4
4 = 6(-4) + c
4 = -24 + c
c = 28
The slope-intercept form of the equation of the straight line is thus;
y = 6x + 28
