Answer:
The speed of faster cyclist is 85.6 m/h
The speed of slower cyclist is 78.6 m/h
Step-by-step explanation:
Given as :
The total distance between two cyclist = d = 123 miles
The Time taken by cyclist to move apart = t = 3 hours
Let The speed of faster cyclist = s miles per hour
And The speed of slower cyclist = (s - 7) miles per hour
<u>Now, According to question</u>
Time =
So, 3 = +
Or, = +
Or, =
Or, s(s - 7) = 41 (2 s - 7)
Or, s² - 7 s = 82 s - 287
Or, s² - 7 s - 82 s + 287 = 0
Or, s² - 89 s + 287 = 0
<u>Now, Solving this quadratic equation</u>
s =
Or, s =
Or, s = ,
∴ speed = 85.6 m/h , 3.4 m/h
Here we consider 85.6 m/h
So, The speed of faster cyclist = s = 85.6 m/h
And The speed of slower cyclist = s - 7 = 85.6 - 7 = 78.6 m/h
Hence,The speed of faster cyclist is 85.6 m/h
And The speed of slower cyclist is 78.6 m/h Answer