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Alex
3 years ago
13

EASY QUESTION**

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
F(x)= -x^3+x ( don’t add the ^ but replace it with the 3 if you know what i mean )
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The area of the sector of a circle with the radius of 8 cm is 125.6 sq cm the estimate value 3.14 what is the angle of the secto
elena-14-01-66 [18.8K]
 <span>The </span>area<span> of the </span>sector<span> of a </span>circle<span> with a </span>radius<span> of </span>8 centimeters<span> is </span>125.6 square centimeters<span>. The </span>estimated value<span> of is </span>3.14<span>. ... First find the </span>area<span> of the entire </span>circleA=3.14*82<span>=200.96 </span>cm2<span> this is the </span>area<span> for 360</span>o<span> or entire </span>circle<span>. The </span>area<span> of the </span>sector<span> represents an</span>angle<span> less then 360 and is simply the ratio of ...</span>
8 0
3 years ago
NEED HELP ASAP!!
devlian [24]

Answer:we multiply by the reciprocal of a fraction when completing a division problem because it is a rule in mathematics that when you divide two fraction, you change the division sign to multiplication and flip the fraction at the right of the multiplication sign.

Step-by-step explanation:

For example if you have 4÷ 1/2. It basically means how many 1/2 can one get in 4. And the answers is 8.

Therefore multiplying by the reciprocal of a fraction when completing a division problem is a short cut method that has been tested and proven to be correct.

4 0
3 years ago
How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y
son4ous [18]

Solution:

Given:

x^2=6y

Part A:

The vertex of an up-down facing parabola of the form;

\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}

Rewriting the equation given;

\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\  \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\  \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\  \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\  \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}

Therefore, the focus is;

(0,\frac{3}{2})

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

\begin{gathered} 4p(y-k)=(x-h)^2 \\  \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}

Rewriting the equation in standard form,

\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}

Therefore, the directrix is;

y=-\frac{3}{2}

3 0
11 months ago
Subtract. Write your answer in simplest form.<br><br> 6 3/4 - 2 3/20<br><br> I need a mixed number
umka21 [38]

Answer:

4 3/5

Step-by-step explanation:

6 3/4-2 3/20=x

3/4=15/20

15/20-3/20=12/20=6/10=3/5

6-3=3+3/5=4 3/5

6 0
2 years ago
Read 2 more answers
a survey asked 72 randomly chosen students if they were going to attend the school play. twelve said yes. if there are 210 ticke
Ugo [173]
We can solve this by setting up a proportion:

12 seeing the play/ 72 students = 210 seeing the play/ x students

We can cross multiply to solve for x:

(12)x=(72)(210)
12x=15,120
x=1,260 students who attend the school
4 0
3 years ago
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