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weeeeeb [17]
3 years ago
15

Ruth took ten nickels from her coin jar and put them in her pocket. Only one of the nickels is dated 2006. When she reaches into

her pocket for a nickel, what is the probability that she will pull out the 2006 nickel?
A.
1
2


B.
1
5


C.
1
10


D.
1
20
Mathematics
2 answers:
ladessa [460]3 years ago
6 0

Answer: I think its C :1-10

Step-by-step explanation:

Lubov Fominskaja [6]3 years ago
5 0

Answer:

Your answer is C. 1/10

Step-by-step explanation:

Your answer is c because there are 10 different coins which is the denominator.

and their is 1 nickel with 2006 which the numerator so your answer is C 1/10

Hope this helps

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How do I get the answer to number 4
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Hello,

You have 7 balloons and in total, they cost 9.1. dollars. To find the unit price per balloon simply divide 9.1. by 7.

You'll get 1.3, OR 1.30. 

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Thus, the unit price per balloon is $1.30.


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Find the slope-intercept equation of the line that has a slope of -2 and goes through the point (5,-2).
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330% of what number is 92.4?
alexgriva [62]

Answer:

92.4/3.3 = 28

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Step-by-step explanation:

5 0
3 years ago
Find an exact value.
Westkost [7]

Answer:

\displaystyle \cos\left(-\frac{7\,\pi}{12}\right) = \frac{\sqrt{2} - \sqrt{6}}{4}.

Step-by-step explanation:

Convert the angle \displaystyle \left(-\frac{7\, \pi}{12}\right) to degrees:

\displaystyle \left(-\frac{7\, \pi}{12}\right) = \left(-\frac{7\, \pi}{12}\right) \times \frac{180^\circ}{\pi} = -105^\circ.

Note, that \left(-105^\circ\right) is the sum of two common angles: \left(-45^\circ\right) and \left(-60^\circ\right).

  • \displaystyle \cos\left(-45^\circ\right) = \cos\left(45^\circ\right) = \frac{\sqrt{2}}{2}.
  • \displaystyle \cos\left(-60^\circ\right) = \cos\left(60^\circ\right) = \frac{1}{2}.
  • \displaystyle \sin\left(-45^\circ\right) = -\sin\left(45^\circ\right) = -\frac{\sqrt{2}}{2}.
  • \displaystyle \sin\left(-60^\circ\right) = -\sin\left(60^\circ\right) = -\frac{\sqrt{3}}{2}.

By the sum-angle identity of cosine:

\cos(A + B) = \cos(A)\cdot \cos(B) - \sin(A) \cdot \sin(B).

Apply the sum formula for cosine to find the exact value of \cos\left(-105^\circ \right).

\begin{aligned}\cos\left(-105^\circ \right) &= \cos\left(\left(-45^\circ\right) + \left(-60^\circ\right)\right) \\ &= \cos\left(-45^\circ\right) \cdot \cos\left(-60^\circ\right)\right) - \sin\left(-45^\circ\right) \cdot \sin\left(-60^\circ\right)\right) \\ &= \frac{\sqrt{2}}{2} \times \frac{1}{2} - \left(-\frac{\sqrt{2}}{2}\right)\times \left(-\frac{\sqrt{3}}{2}\right) = \frac{\sqrt{2} - \sqrt{6}}{4}\end{aligned}.

\displaystyle \left(-\frac{7\, \pi}{12}\right) = \left(-\frac{7\, \pi}{12}\right) \times \frac{180^\circ}{\pi} = -105^\circ. In other words, \displaystyle \left(-\frac{7\, \pi}{12}\right) and \left(-105^\circ\right) correspond to the same angle. Therefore, the cosine of \displaystyle \left(-\frac{7\, \pi}{12}\right)\! would be equal to the cosine of \left(-105^\circ\right)\!.

\displaystyle \cos\left(-\frac{7\,\pi}{12}\right) = \cos\left(-105^\circ\right) = \frac{\sqrt{2} - \sqrt{6}}{4}.

3 0
2 years ago
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