Problem One
Call the radius of the second can = r
Call the height of the second can = h
Then the radius of the first can = 1/3 r
The height of the first can = 3*h
A1 / A2 = (2*pi*(1/3r)*(3h)] / [2*pi * r * h]
Here's what will cancel. The twos on the right will cancel. The 3 and 1/3 will multiply to one. The 2 r's will cancel. The h's will cancel. Finally, the pis will cancel
Result A1 / A2 = 1/1
The labels will be shaped differently, but they will occupy the same area.
Problem Two
It seems like the writer of the problem put some lids on the new solid that were not implied by the question.
If I understand the problem correctly, looking at it from the top you are sweeping out a circle for the lid on top and bottom, plus the center core of the cylinder.
One lid would be pi r^2 = pi w^2 and so 2 of them would be 2 pi w^2
The region between the lids would be 2 pi r h for the surface area which is 2pi w h
Put the 2 regions together and you get
Area = 2 pi w^2 + 2 pi w h
Answer: Upper left corner <<<<< Answer
Answer:
3/2
Step-by-step explanation:
Y2-Y1
_____
X2-X1
= 5-2
____
-6-(-3)
=3/2
Answer:
Polygon Name
Number of Interior Angles
Sum of Interior Angles = (n-2) x 180°
Triangle
3
180°
Quadrilateral
4
360°
<u><em> Pentagon </em></u>
<u><em> 5 </em></u>
<u><em> 540° </em></u>
Hexagon
6
720°
Step-by-step explanation:
Answer: 25 games
Step-by-step explanation:
Take the fractions 76/100 and 19/x
Cross multiply. 76 times x equally 76x and 100 times 19 equals 1900.
Divide 76x by 76 which equals just x.
Divide 1900 by 76 which equals 25.
x=25
Answer:
The purpose of a trial balance is to prove that the value of all the debit value balances equals the total of all the credit value balances. If the total of the debit column does not equal the total value of the credit column then this would show that there is an error in the nominal ledger accounts.
Step-by-step explanation:
