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Gre4nikov [31]
3 years ago
5

The ratio of white chocolate to dark chocolate sold at a candy shop was 4 : 3. If there were 20 bars of white chocolate sold, ho

w many bars of dark chocolate were sold?
Mathematics
1 answer:
Ksju [112]3 years ago
5 0

Answer:

15

Step-by-step explanation:

if the white chocolate is the 4 you would need to multiply it by 5 to get 20 so if u multiply 3 by 5 you get 15 hope this helps :)

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Mary bought these art supplies: 4 paint brushes @ $1.29 each, 6 dowel rods @ $1.49 each, a jar of paste @ $1.25, and 2 canvases
Sophie [7]

Answer:

Option (1) is correct

The amount she receives back from $40 is  $12.65

Step-by-step explanation:

Given: Mary bought the art supplies.

4 paint brushes @ $1.29 each, 6 dowel rods @ $1.49 each, a jar of paste @ $1.25, and 2 canvases @ $6.00 each.

We have to find the change she get from $40.

We first find the total cost of the art supplies.

Since, she brought 4 paint brushes @ $1.29 each,

Thus, cost of 4 paint brush is  1.29 × 4 = $5.16

Also, 6 dowel rods @ $1.49 each,

Thus, cost of 6 dowel rods is  1.49 × 6 = $8.94

Thus, cost of 1 jar of paste  is $1.25

and 2 canvases @ $6.00 each

Thus, cost of 2 canvases  is $12.00

Thus, total cost of art supplies = 5.16 + 8.94 + 1.25 + 12 =$27.35

Thus, amount she receives back from $40 is $40 - $12.35 = $12.65

4 0
3 years ago
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Perpendicular lines are defined as
BartSMP [9]
Lines that overlap each other opposite like a T or +
6 0
3 years ago
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sarah worked out for 15 today. she plans to add 5 min per week. write qnd equation to represent how many minutes she will be wor
garik1379 [7]

Answer:

I think its 15 + 5x

Step-by-step explanation:

4 0
3 years ago
What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?
jolli1 [7]

Answer:

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given  : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For  2d + 3 ≤ –11

On subtracting both sides by 3

2d  ≤ –11 - 3 .

2d  ≤ –14.

On dividing both sides by 2 .

d  ≤ –7.

For  3d – 9 > 15.

On adding both sides by 9.

3d > 15 + 9 .

3d > 24 .

On dividing both sides by 3 .

d > 8 .

So, A. d ≤ –7 or d > 8.

Therefore,  A. d ≤ –7 or d > 8.

7 0
3 years ago
Please help answer these questions
vfiekz [6]

<u>Step</u><u> </u><u>1</u>

given

<u>Step</u><u> </u><u>2</u>

\angle HKM \cong \angle OKM, \angle HMK \cong \angle OMK

<u>Step</u><u> </u><u>3</u>

\overline{KM} \cong \overline{KM}

Reason: Reflexive property

<u>Step</u><u> </u><u>4</u>

ASA

8 0
2 years ago
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