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Svet_ta [14]
3 years ago
11

What is 83 x 96 fzoigjwcsvgfmcgksjkvzmclkm

Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0
7968 because you multiply the two numbers to get the final answer
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A fish tank holds at most 125 gallons of water. The tank already has 20 gallons of water in it when Ian begins to fill it at a r
ivolga24 [154]

Answer:

ttgfuytggghghhhtxjfhfughfhfgfhg

3 0
3 years ago
A scientist measures the distance, in feet, between animals and the surface of a pond.
aleksandr82 [10.1K]

Considering the opposite of the rational number -1/2, the location of the snail is represented by the number 1/2.

<h3>What is the missing information?</h3>

This problem is incomplete, but researching it on a search engine, we have that:

  • The fish is located at -1/2 feet.
  • The snail is located at the opposite location of the fish.

<h3>What is the opposite of a rational number?</h3>

The opposite of a rational number a is given by -a, that is, it is the number with the opposite signal.

Hence, the <u>opposite of -1/2 is 1/2</u>, and the location of the snail is represented by the number 1/2.

More can be learned about rational numbers at brainly.com/question/13325494

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4 0
2 years ago
In physics, pressure is the amount of force exerted on a surface per unit area, P = StartFraction F Over A EndFraction The press
Zina [86]

Answer:

Answer is C on ed2020

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Fine the surface of one yard.<br><br>please help .-.
ale4655 [162]

Answer:

1) 34 square meters

2) 21 square yards

Step-by-step explanation:

1) 7x4=28

1/2x3x2x2=6

28+6= 34 square meters

2)3x3=9

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6 0
2 years ago
Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant​ criteria?Tem
Xelga [282]

Answer:

B. No, this distribution does not appear to be normal

Step-by-step explanation:

Hello!

To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.

The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.

As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.

The answer is B.

I hope it helps!

3 0
3 years ago
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