4 years ago

Find the zeros of the function f(x)=8x^2 +32

Mathematics

1 answer:

Sholpan [36]4 years ago

5 0

Answer: no solution

Step-by-step explanation:

$8x^{2} +32=0$

Factor out 8

$8(x^{2} +4)=0$

no solution

Why?

Think about the graph, $x^{2}$ shifted up 4 has no zeros, even with a vertical stretch of 8.

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Given: ABCD is a trapezoid, AB = CD, BK ⊥ AD, AK = 10, KD = 20 Find: BC AD

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Step-by-step explanation:

In figure-1 , AB = CD ,BK ⊥ AD, AK = 10, KD = 20.

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