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Nat2105 [25]
3 years ago
14

Roman mixes 12 liters of 8% acid solution with a 20% acid solution, which results in a 16% acid solution. Find the number of lit

ers of 20% acid solution in the new mixture. Construct a table to organize the information, and show all of your work to solve the problem.
Please help me with the table part!
Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0
We have 12 liters of 8% acid solution to which we add an unknown amount of liters (x) of 20% acid solution to make a 16% acid solution.
.08 * 12 +.20x = .16 * (12 +x)
.96 + .20x = 1.92 + .16x
.04x = .96
x = 24 liters of 20% acid solution must be added

Source http://www.1728.org/mixture.htm
see example B



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<u>800 liters</u> of 90% saline solution and <u>1200 liters</u> of 40% saline solution should be used.

Step-by-step explanation:

Given:

At 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution.

Now, to find the number of liters of saline solution each should be used.

<u><em>Let the liters of 90% saline solution mix be </em></u>x.<u><em /></u>

<u><em>And let the liters of 40% saline solution mix be</em></u> y.

So, the total number of liters:

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Now, the total percentage of saline solution:

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\frac{90}{100}\times x+\frac{40}{100}\times y=\frac{60}{100}\times 2000

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Substituting the value of y from equation (1) we get:

0.9x+0.4(2000-x)=1200

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Subtracting both sides by 800 we get:

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Dividing both sides by 0.5 we get:

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<u>The liters of 90% saline solution mix = 800.</u>

Now, substituting the value of x in equation (1) to get the liters of 40% saline solution:

y=2000-x

y=2000-800

y=1200.

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Therefore, 800 liters of 90% saline solution and 1200 liters of 40% saline solution should be used.

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Answer:

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