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2 years ago

Can you please help me with this question please and i will give you a Brainiest

Mathematics

1 answer:

elena-14-01-66 [18.8K]2 years ago

4 0

Answer:

30 more queen bee books have been sold.

Explanation:

60 queen bee books have been sold.

30 Jade Owl books have been sold.

We need to work out the difference to find out how many more Queen Bee books have been sold. 60 - 30=30

Hope this helps :D

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HELPP PLEASE AND GET POINTS

MArishka [77]

Answer:

112

Step-by-step explanation:

cause if you calculated it it will be 112.2222 so the closest thing is 112

3 0

2 years ago

Show that if X is a geometric random variable with parameter p, then

Lubov Fominskaja [6]

Answer:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

In order to find the expected value E(1/X) we need to find this sum:

$E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}$

Lets consider the following series:

$\sum_{k=1}^{\infty} b^{k-1}$

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

$\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}$ (a)

On the last step we assume that $0\leq r\leq b$ and $\sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}$ , then the integral on the left part of equation (a) would be 1. And we have:

$\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)$

And for the next step we have:

$\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}$

And with this we have the requiered proof.

And since $b=1-p$ we have that:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

4 0

2 years ago

PLEASE HELP

katrin [286]

Answer:

3 + 4n -9 + 5n

9n - 6

3 0

2 years ago

Solve the system of equations. <br> 3x-4y=8 <br> 18x-5y=10

ipn [44]

Answer:

y = -2 x = 0

Step-by-step explanation:

1. 3x-4y = 8

2. 18-5y = 10

Multiply equation 1 by 6

3. 18x-24y = 48

Subtract equation 2 from equation 3

4. -19y = 38

y = 38/-19

y = -2

Sub y = -2 back into equation 1

3x-4(-2) = 8

3x + 8 = 8

3x = 0

x = 0/3

x = 0

7 0

2 years ago

What is the sum of 36(6 - 4) and 6(6 – 8)?

Dmitry_Shevchenko [17]

Answer:

Your answer would be 60

Step-by-step explanation:

=36(6 - 4) 6(6 – 8)

= 36(2) + 6 (-2)

= 72 + (-12)

= 72 - 12

= 60

hope it helps!

6 0

2 years ago