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PIT_PIT [208]
3 years ago
9

Z2-y2=x2 solve for z2 (literal equation)

Mathematics
1 answer:
expeople1 [14]3 years ago
5 0

Answer:

z² = x² + y²

Step-by-step explanation:

Given

z² - y² = x² ( isolate z² by adding y² to both sides )

z² = x² + y²

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I have 30 ones, 2 thousands, 4 hundreds, 60 tens, and 100 hundreds. what number am I?
Kobotan [32]

Answer:

2590

Step-by-step explanation:

30+2000+400+60+100

8 0
3 years ago
According to a study, 50 % of adult smokers started smoking before 21 years old. 5 smokers 21 years old or older are randomly se
belka [17]

Answer:

a) The probability that at least 2 of them started smoking before 21 years of age is 0.1875 = 18.75%.

b) The probability that at most 4 of them started smoking before 21 years of age is 0.96875 = 96.875%.

c) The probability that exactly 3 of them started smoking before 21 years of age is 0.3125 = 31.25%.

Step-by-step explanation:

For each smoker, there are only two possible outcomes. Either they started smoking before 21 years old, or they did not. Smokers are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of adult smokers started smoking before 21 years old.

This means that p = 0.5

5 smokers 21 years old or older are randomly selected, and the number of smokers who started smoking before 21 is recorded.

This means that n = 5.

a) The probability that at least 2 of them started smoking before 21 years of age is

This is:

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125

P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625

P(X < 2) = P(X = 0) + P(X = 1) = 0.03125 + 0.15625 = 0.1875

The probability that at least 2 of them started smoking before 21 years of age is 0.1875 = 18.75%.

b) The probability that at most 4 of them started smoking before 21 years of age is

This is:

P(X \leq 4) = 1 - P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125

P(X \leq 4) = 1 - P(X = 5) = 1 - 0.03125 = 0.96875

The probability that at most 4 of them started smoking before 21 years of age is 0.96875 = 96.875%.

c) The probability that exactly 3 of them started smoking before 21 years of age is

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125

The probability that exactly 3 of them started smoking before 21 years of age is 0.3125 = 31.25%.

4 0
3 years ago
A pole is made to lean against a wall. The base of the pole is placed 7 feet
Brums [2.3K]

Answer:

22.14

Step-by-step explanation:

Using the Pythagorean Theorem:

a^2 + b^2 = c^2

21^2 + 7^2 = c^2

441 + 49 = c^2

490 = c^2 (square root both sides so c^2 becomes c)

c = 22.13594363 (round to hundredths)

c = 22.14

6 0
3 years ago
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tatuchka [14]

Answer:

39 degrees

Step-by-step explanation:

97+44= 141

141 - 180 = 39

8 0
3 years ago
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Please help me, I am lost from 3.2 going down
pentagon [3]
Don't click the link
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