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4 years ago

Which measurement is NOT equivalent to the others? *

1 answer:

3 0

Your answer is 199cm is not equal because of 10mm equal 1cm and 100cm equal 1 meter and 100,000cm equal 1 km. Hope this helps.

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Is -4x-1 over 4=1 inverse

sammy [17]

Answer:

no because (-4x-1)=4+1

Step-by-step explanation:

8 0

3 years ago

What is the area of a circular region whose diameter is 10 centimeters?

stepan [7]

Answer:

78cm

Step-by-step explanation:

d = 10

area of a circle = πr^2

22/7 × 5 × 5

78.5cm

6 0

3 years ago

The amount of paper that the copy shop used this month was a 25% increase of the amount of paper they used last month. What perc

likoan [24]

Answer:

You didn't include any image here, but numerically, the amount of paper consumed this month is 125% compared to last month.

If last month's consumption is represented by 4 equal shapes, then the current month's consumption will be 5 shapes.

If last month's consumption is represented by 8 equal shapes, then the current month's consumption will be 10 shapes.

this pattern keeps repeating.

3 0

3 years ago

Suzy Little was just 3 years old when Uncle Beanie opened an account. He deposited $25, compounded daily. When she was 18 and of

Tresset [83]

Answer:

idont know what to do with the fact

5 0

3 years ago

A square has side length of 9 in. If the area is doubled, what happens to the side length?

Alika [10]

Answer:

The side length is multiplied by $\sqrt{2}$

Step-by-step explanation:

we know that

The area of the original square is equal to

$A=9^{2}=81\ in^{2}$

If the area is doubled

then

The area of the larger square is

$A1=(2)81=162\ in^{2}$

Remember that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the larger square

y ---> the area of the original square

$z^{2}=\frac{x}{y}$

we have

$x=162\ in\^{2}$

$y=81\ in\^{2}$

$z^{2}=\frac{162}{81}$

$z^{2}=2$

$z=\sqrt{2}$ ------> scale factor

therefore

The side length is multiplied by $\sqrt{2}$

7 0

3 years ago