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gogolik [260]
3 years ago
11

Suppose a set of test scores is appproximately bell-shaped, with a mean of 68 and a range of 54. (a) The minimum test score is a

pproximately , and the maximum test score is approximately . (b) The standard deviation of the test scores is approximately g
Mathematics
1 answer:
liberstina [14]3 years ago
7 0

Answer:

a.) Minimum test score = 41

    Maximum test score = 95

b.)An approximate value of the standard deviation is 9.

Step-by-step explanation:

The given set of test scores is approximately bell shaped.

The mean of the test scores, \mu = 68

The range of the data set = 54.

a.) i.) Minimum test score  = \mu - \frac{range}{2}  = 68 - \frac{54}{2}  = 68 - 27 = 41

   ii.) The maximum test score = \mu + \frac{range}{2}  = 68 + \frac{54}{2}  = 68 + 27 = 95

b.) From the 68-95-99.7 rule, also known as the Empirical rule, tell us that an approximation of the range is 3 standard deviations either way from the mean. So from this rule we can say that the minimum can also be found from \mu - 3\sigma and the maximum can also be approximated as \mu + 3\sigma.

From the above we can say that the range can be written as

   3\sigma - (-3\sigma) = range

∴   6\sigma  = range

∴    \sigma  = \frac{range }{6}  = \frac{54}{6}  = 9

Therefore an approximate value of the standard deviation is 9.

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-25^-1/2 with explanation please
slavikrds [6]

Answer:

The simplified value of -25^{-\frac{1}{2}} is -\frac{1}{5}.

Step-by-step explanation:

As the given expression is

-25^{-\frac{1}{2}}

Lets simplify this expression step by step

As

-25^{-\frac{1}{2}}....[A]

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

25^{-\frac{1}{2}}=\frac{1}{25^{\frac{1}{2}}}

So, lets plug 25^{-\frac{1}{2}}=\frac{1}{25^{\frac{1}{2}}} in equation [A] i.e.  -25^{-\frac{1}{2}}....[A]

-25^{-\frac{1}{2}}....[A]

=-\frac{1}{25^{\frac{1}{2}}}        ∵ 25^{-\frac{1}{2}}=\frac{1}{25^{\frac{1}{2}}}

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Therefore, the simplified value of -25^{-\frac{1}{2}} is -\frac{1}{5}.

Keywords: simplification, exponent rule

Learn more about expression simplification from brainly.com/question/13848834

#learnwithBrainly

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