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gogolik [260]
3 years ago
11

Suppose a set of test scores is appproximately bell-shaped, with a mean of 68 and a range of 54. (a) The minimum test score is a

pproximately , and the maximum test score is approximately . (b) The standard deviation of the test scores is approximately g
Mathematics
1 answer:
liberstina [14]3 years ago
7 0

Answer:

a.) Minimum test score = 41

    Maximum test score = 95

b.)An approximate value of the standard deviation is 9.

Step-by-step explanation:

The given set of test scores is approximately bell shaped.

The mean of the test scores, \mu = 68

The range of the data set = 54.

a.) i.) Minimum test score  = \mu - \frac{range}{2}  = 68 - \frac{54}{2}  = 68 - 27 = 41

   ii.) The maximum test score = \mu + \frac{range}{2}  = 68 + \frac{54}{2}  = 68 + 27 = 95

b.) From the 68-95-99.7 rule, also known as the Empirical rule, tell us that an approximation of the range is 3 standard deviations either way from the mean. So from this rule we can say that the minimum can also be found from \mu - 3\sigma and the maximum can also be approximated as \mu + 3\sigma.

From the above we can say that the range can be written as

   3\sigma - (-3\sigma) = range

∴   6\sigma  = range

∴    \sigma  = \frac{range }{6}  = \frac{54}{6}  = 9

Therefore an approximate value of the standard deviation is 9.

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Answer:

so if the number was 3 red marbles and 5 blue marbles the ratio would be 3:5

Step-by-step explanation:

3 0
3 years ago
Suppose that you construct a histogram and a relative frequency histogram corresponding to a particular frequency table. Identif
Korolek [52]
The histogram will give the actual number of items in each interval. This is called the frequency.

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3 years ago
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In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t
AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

         r = no. of success which is at least 5 in our case

         p = probability of success which is probability of Roman Catholic of

                 0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0
3 years ago
Please help out and if you know help me show work ??
Ghella [55]

Answer:  14

<u>Step-by-step explanation:</u>

Consecutive even numbers would be {2, 4, 6, 8, 10, ...}

Let x represent the smallest number, then x + 2 is the middle number and x + 4 is the largest number.

1st number: x

2nd number: x + 2

3rd number: x + 4

1st number + 2nd number + 3rd number = Sum

      (x)        +      (x + 2)       +      (x + 4)      =  48

                                                      3x + 6   =  48

                                                      3x          = 42

                                                        x           = 14

1st number: x           ⇒ x = 14

2nd number: x + 2   ⇒ 14 + 2 = 16

3rd number: x + 4    ⇒ 14 + 4 = 18

<u>Check:</u>

14 + 16 + 18 = 48 \checkmark

 

7 0
3 years ago
HELP ME OUTT PPL (BRAINIEST)
Annette [7]

Answer:

(0, 6)

Step-by-step explanation:

Point T is at (3, 4), and three units to the left would be (0, 4). They then tell us to go two points up, which would change the ordered pair to (0, 6).

I hope this was helpful! Have a lovely day! :D

3 0
2 years ago
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