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belka [17]
3 years ago
11

1.) Which domain restrictions apply to the rational expression? 14x-2x / x^2-7x

Mathematics
1 answer:
mezya [45]3 years ago
5 0

Answer:

3. \displaystyle 1\frac{1}{3} = x

2<em>C.</em> \displaystyle III.

2<em>B.</em> \displaystyle I.

2<em>A.</em> \displaystyle II.

1. \displaystyle Set-Builder\:Notation: [x|7, 0 ≠ x] \\ Interval\:Notation: (-∞, 0) ∪ (0, 7) ∪ (7, ∞)

Step-by-step explanation:

3. <em>See</em><em> </em><em>above</em>.

2<em>C</em>. The keyword is ratio, which signifies division, so you would choose "III.".

2<em>B</em>. The keyword is percent, which signifies multiplication of a ratio by 100, so you would choose "I.".

2<em>A</em>. The keyword is total, which signifies addition, so you would choose "II.".

1. Base this off of the denominator. Knowing that the denominator CANNOT be zero, you will get this:

\displaystyle x^2 - 7x \\ x[x - 7] = 0; 7, 0 = x \\ \\ Set-Builder\:Notation: [x|7, 0 ≠ x] \\ Interval\:Notation: (-∞, 0) ∪ (0, 7) ∪ (7, ∞)

I am joyous to assist you anytime.

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Find the 75th term of the arithmetic sequence -1, 15, 31, ...−1,15,31,...
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Answer:

1183

Step-by-step explanation:

Common difference:

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3 years ago
Please help need answers
bogdanovich [222]

see explanation below

(1) \frac{1}{5} × \frac{2}{2} = \frac{2}{10} = 0.2

(2) \frac{6}{25} × \frac{4}{4} = \frac{24}{100} = 0.24

(3) 2 \frac{3}{4} = 2 +\frac{75}{100} = 2.75

(4) 3 \frac{9}{10} = 3 + 0.9 = 3.9

(5) 1.25 = 1 \frac{1}{4} = \frac{5}{4}

(6) 3.29 = 3 \frac{29}{100} = \frac{329}{100}

(7) 0.65 = \frac{65}{100} = \frac{13}{20} in simplest form

(8) 5.6 = 5 \frac{6}{10} = 5 \frac{3}{5} = \frac{28}{5}

(9) he is incorrect

\frac{3}{5} × \frac{20}{20} = \frac{60}{100} = 0.6 ≠ 3.5


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