Answer:
It would be b I think
Step-by-step explanation:
Answer: 0.1357
Step-by-step explanation:
Given : Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of
and a mean life span of
hours.
Here , 
Let x represents the life span of a monitor.
Then , the probability that the life span of the monitor will be more than 14,650 hours will be :-
![P(x>14650)=P(\dfrac{x-\mu}{\sigma}>\dfrac{14650-13000}{1500})\\\\=P(z>1.1)=1-P(z\leq1.1)\ \ [\because\ P(Z>z)=1-P(Z\leq z)]\\\\=1-0.8643339=0.1356661\approx0.1357](https://tex.z-dn.net/?f=P%28x%3E14650%29%3DP%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B14650-13000%7D%7B1500%7D%29%5C%5C%5C%5C%3DP%28z%3E1.1%29%3D1-P%28z%5Cleq1.1%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.8643339%3D0.1356661%5Capprox0.1357)
Hence, the probability that the life span of the monitor will be more than 14,650 hours = 0.1357
Answer:
24
Step-by-step explanation:
BD=DC
5x-26=2x+1
5x-2x=1+26
3x=27
x=9
BC=2x+1
=2*9+1
BC =19
so AB=AC-BC
AB=43-19
AB=24
Let the width be x
The length would be 2x-5
So, 2(x+2x-5)=80
3x-5=40
3x=45
x=15.
So the width is 15 and the length would be 25.