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Andre45 [30]
3 years ago
9

PLEASE HELP Given that ABCD is a parallelogram, what must be proven to prove that the diagonals bisect each other?

Mathematics
2 answers:
nalin [4]3 years ago
7 0

Answer with explanation:

To prove that , the diagonals of Parallelogram ,A B CD,Bisect each other

That is, 1. A O=OD

   2. BO=O C

We need to prove ,that either of two triangles

1. ΔA OB ≅ Δ DOC

or

2.  ΔA O C ≅ Δ DOB

We will prove ,ΔA OB ≅ Δ DOC , in the following way.

1.∠A OB ≅ ∠ DOC→→→[Vertically Opposite angles]

2. AB=CD →→→[Opposite sides of parallelogram]

3. ∠BAD=∠C DA→[As, AB║CD,so Alternate interior angles are equal.]

⇒ΔA OB ≅ Δ DOC→→→ [A A S]

So, A O=OD→→[C PCT]

and, CO=OD→→[C PCT]

Similarly,we can prove that, ΔA O C ≅ Δ DOB,and get

   A O=OD

and, CO=OD

To prove that,diagonals bisect each other of a Parallelogram,we need to prove

D)  A O≅OD

mixer [17]3 years ago
6 0
Dxxdyjojo18 I Think its D
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Step-by-step explanation:

A full circle is 360 degrees, so if the segment has an arc of 120 degrees, it is 1/3 of a regular circle.

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2 years ago
X(x+3) + 34 = (x +5)(x+2)
My name is Ann [436]
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Third, cancel out 'x^{2}' on both sides.
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Fourth, subtract '3x' from both sides.
34 = 7x + 10 - 3x
Fifth, subtract '7x - 3x' to get '4x'.
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