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g100num [7]
3 years ago
10

Solve 5n^2=5 with the quadratic formula

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

n = 1

Step-by-step explanation:

First, rearrange the equation to standard form 0 = ax² + bx + c, when everything equals 0.

5n² = 5

5n² - 5 = 0

State the variables a, b and c.

a = 5;  b = 0;  c = -5

Substitute a, b, and c into the quadratic formula.

n = \frac{-b ±\sqrt{b^{2}-4ac} }{2a}

n = \frac{-0 ±\sqrt{0^{2}-4(5)(-5)} }{2(5)}   Substitute

n = \frac{\sqrt{100} }{10}   Simplify inside the √ and bottom

n = \frac{10}{10}  Simplify the top

n = 1  Final answer

Therefore the solution is n = 1.

The quadratic formula usually is written with x, but it can be solved with any variable in standard form.

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10. 10x + 5y = 15<br> y=2x-3
Ivan

Answer:

(i think) 1.5

Step-by-step explanation:

If you replace y with the equation y=2x-3, you get 5(2x - 3)

if you distribute this, it equals 10x - 15

combining like terms 10x + 10x - 15=15 will turn into 20x - 15 = 15

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6 0
3 years ago
How do u work this out and what's the answer
I am Lyosha [343]
1) you would need to turn both fractions so they have a common denominator, that would be 2 2/4 and 3/4
2) then subtract : 2 2/4 - 3/4, and you would subtract numerators and the whole number, but you keep the denominator the same. However, you cannot subtract 2 and 3 in this case, so you need to change 2 2/4 to 1 5/4 (they are still equivalent)
3) 1 5/4 - 3/4 = 1 2/4, which simplified version is 1 1/2
Therefore, the answer is 1 and 1/2
6 0
3 years ago
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