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egoroff_w [7]
2 years ago
15

Evaluate the expression when c=4 and d=48. d-6c​

Mathematics
1 answer:
Rama09 [41]2 years ago
5 0

Answer:

24

Step-by-step explanation:

since c=4 and d=48, we can re-write this equation

48-6 x 4

48 - 24

24

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x^2+5x-1=0\\x^2+5x+(\frac{5}{2})^2-(\frac{5}{2})^2-1=0\\(x+\frac{5}{2})^2-\frac{25}{4}-\frac{4}{4}=0\\(x+\frac{5}{2})^2-\frac{29}{4}=0\\(x+\frac{5}{2})^2=\frac{29}{4}\\x+\frac{5}{2}=\sqrt{\frac{29}{4}} , x+\frac{5}{2}=-\sqrt{\frac{29}{4}}\\x=\frac{\sqrt{29} }{2} - \frac{5}{2} , x=-\frac{\sqrt{29} }{2} - \frac{5}{2} \\x=\frac{\sqrt{29}-5 }{2} , x=-\frac{\sqrt{29} -5}{2}

4 0
3 years ago
Find the perimeter of a quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).
antoniya [11.8K]

The perimeter of the quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3) is 20units.

Option C) is the correct answer.

<h3>What a quadrilateral?</h3>

A quadrilateral is simply a polygon with four sides, four angles, and four vertices.

To get the perimeter, we simply add the values of the four side.

Given that;

The vertices are at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).

To get the dimension between the given coordinates, we use;

 d = √((x2 -x1)² +(y2 - y1)²)

For length CD, DE, EF and FC

CD = √((2 - (-2))² + (4 - 1)²) = √( 16+9) = √25 = 5

DE = √((5 - 2)² + (0 - 4)²) = √( 9+16) = √25 = 5

EF = √((1 - 5)² + (-3 - 0)²) = √( 16+9) = √25 = 5

FC = √((-2 - 1)² + ( 1 - (-3))²) = √( 9+16) = √25 = 5

Perimeter of the quadrilateral = CD + DE + EF + FC

Perimeter of the quadrilateral = 5 + 5 + 5 + 5

Perimeter of the quadrilateral = 20units

Therefore, the perimeter of the quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3) is 20units.

Option C) is the correct answer.

Learn more about area of rectangle here: brainly.com/question/27612962

#SPJ1

6 0
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B. is the answer dude
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