Answer:
A) answer c ; B) X+3.7=15.3 ; C) 15.3 - 3.7 = 11.6 ---> 11.6+3.7=15.3
Step-by-step explanation:
Solution for A: First you have to look for the line underneath the bar says 15.3 as this will represent the total amount of liters in the bucket altogether. This would be bar c since we also know that we have 3.7 liters added but are missing the amount that was previously inside the bucket.
Solution for B: Let X resemble the unknown amount of water. To solve B, we need to write an equation. We know that there was already an amount of water in the bucket prior to us pouring more in so X is our first addend. We then added 3.7 liters of water to the unknown amount so that is our next addend giving you X+3.7=15.3
Solution for C: Now that we know our equation, we do the inverse operation (subtraction) in order to figure out the missing amount of water. This means we do
15.3 - 3.7 = 11.6
Answer: a) No Solution
b) Infinite Solutions (All Real Numbers)
<u>Step-by-step explanation:</u>
4(g + 8) = 7 + 4g
4g + 32 = 7 + 4g <em>distributed 4 into g + 8</em>
32 = 7 <em> subtracted 4g from both sides</em>
Since the statement is false because 32 ≠ 7, then there is NO SOLUTION
-4(-5h - 4) = 2(10h + 8)
20h + 16 = 20h + 16 <em>distributed</em>
16 = 16 <em>subtracted 20h from both sides</em>
Since the statement is true because 16 = 16, then there are INFINITE SOLUTIONS so x can be all real numbers.
Answer:
1/3 or 33.33 %
Step-by-step explanation:
this is because there is 30 shirts and all and 10 white. 10/30 is 1/3, or 33.33%
Answer:
<u>a) x = 3</u>
<u>b) z = 10</u>
<u>c) p = 2</u>
<u>d) x = 7</u>
<u>e) u = 1</u>
Step-by-step explanation:
a) 2x = 6
Despejamos x dividiendo por 2 a amabos lados de la eacuacion.
(2/2)x = 6/2
<u>x = 3</u>
Si remplazamos x en la ecuación original:
2(3)=6
6 = 6
Queda demostrado.
b) 10 + z = 20
Despejamos z restando 10 en amabos lados de la eacuacion.
10-10+z = 20-10
<u>z = 10</u>
Si remplazamos z en la ecuación original:
10 + 10=20
20 = 20
Queda demostrado.
c) p + 9 = 11
Despejamos p restando 9 en amabos lados de la eacuacion.
p + 9 - 9 = 11-9
<u>p = 2</u>
Si remplazamos p en la ecuación original:
2 + 9 = 11
11 = 11
Queda demostrado.
d) 3x + 8 = 29
Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.
3x+8-8 = 29-8
3x = 21
(3/3)x = 21/3
<u>x = 7</u>
Si remplazamos x en la ecuación original:
3(7) + 8 = 29
21 + 8 = 29
29 = 29
Queda demostrado
e) 2u + 8 = 10
Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.
2u+8-8 = 10-8
2x = 2
(2/2)x = 2/2
<u>x = 1</u>
Si remplazamos x en la ecuación original:
2(1) + 8 = 10
2 + 8 = 10
10 = 10
Queda demostrado
Espero te haya sido de ayuda!
Hello,
First we work out the equations:
x + y =62 will be the first equation.
2x= y +13 is the second equation.
We can first rewrite the second equation as 2x – y =13.
So we have:
x + y = 62
2x –y =13
KEEP IN MIND: With y being positive in one of the equations and negative in the other, we can combine the equations to quickly eliminate y and solve for x.
x + y = 62
+2x –y =13
3x = 75 divide both sides by 3 to get x.
x = 25
Now that we have x we can substitute the value for x, 25.
25 + y = 62 we can subtract 25 from both sides to get y.
y = 62- 25
y = 37
2(25) = 37 + 13
Therefore,
50 = 50
Have a amazing day.
