A polynomial function has -5√3i as a root. Which of the following must also be a root of the function?

Mathematics

2 answers:

Hatshy [7]4 years ago

7 0

Answer: is A

Step-by-step explanation:

yan [13]4 years ago

5 0

Answer:

-5+√3i is the given root so -5-√3i must be the other root

Step-by-step explanation:

We know that complex roots must come in pairs. The pairs are complex conjugates. (a+bi) and (a-bi)

You are missing a sign between -5 and the square root

So if - 5+ sqrt(3) i is a root, then -5 - sqrt(3) i must be a root

if -5 - sqrt(3)i is a root, then -5 + sqrt(3)i must be a root.

I will assume you missed a + sign

-5+√3i is the given root so -5-√3i must be the other root

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FrozenT [24]

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⇒ 4g= 32
⇒ g= 32/4
⇒ g= 8

2. c= 5*6
⇒ c= 30

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⇒f+4= 15
⇒ f= 15-4
⇒ f= 11.

4. b+6= 30/5
⇒ b+6= 6
⇒ b= 6-6
⇒ b=0

5. a-5= 60/5
⇒ a-5= 12
⇒ a= 12+5
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6. e+2= 45/5
⇒ e+2= 9
⇒ e= 9-2
⇒ e= 7

7. d-5= 12/3
⇒ d-5= 4
⇒ d= 4+5
⇒ d= 9

8. m-4= 16/4
⇒ m-4= 4
⇒ m= 4+4
⇒ m= 8

9. q+6= 30/5
⇒ q+6= 6
⇒ q= 6-6
⇒ q= 0

10. h/3= 3+5
⇒ h/3= 8
⇒ h= 8*3
⇒ h= 24

11. 3c= 3-5
⇒ 3c= -2
⇒ c= -2/3

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⇒ x/3= -1
⇒ x= -1*3
⇒ x= -3

13. 6p= 2+1
⇒ 6p= 3
⇒ p= 3/6
⇒ p= 1/2

14. 2d-7= 27/3
⇒ 2d-7= 9
⇒ 2d= 9+7
⇒ 2d= 16
⇒ d= 16/2
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⇒ b-3= 2.5
⇒ b= 2.5+3
⇒ b= 5.5

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⇒ y= 1/3+1
⇒ y= 1 1/3

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⇒ v= 6/5
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6 0

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Read 2 more answers

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Licemer1 [7]

Answer:

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Step-by-step explanation:

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