Rewrite the first function so that the two functions are in standard form:
y - 3 = -2x - 8 => y = 3 - 2x - 8 => y = -2x - 5
and
y= -2x - 5
We can now see immediately that these two functions have the same slope (-2) and same y-intercept (providing that you meant "y = -2x - 5).
The graphs of these 2 functions are identical.
The answer is chicken $8, duck $5
x - the cost of a chicken
y - the cost of a duck
<span>he sold 50 chickens and 30 ducks for $550: 50x + 30y = 550
</span><span>he sold 44 chickens and 36 ducks for $532: 44x + 36y = 532
</span>50x + 30y = 550 divide by 10
44x + 36y = 550 divide by 4
______________
50x/10 + 30y/10 = 550/10
44x/4 + 36y/4 = 532/4
______________
5x + 3y = 55 Multiply by (-3)
11x + 9y = 133
______________
5x * (-3) + 3y * (-3) = 55 * (-3)
11x + 9y = 133
______________
-15x - 9y = -165
11x + 9y = 133
______________
Sum up:
-4x + 0y = -32
-4x = -32
x = -32/-4
x = 8
Since 5x + 3y = 55 and x = 8, then:
5 * 8 + 3y = 55
40 + 3y = 55
3y = 55 - 40
3y = 15
y = 15/3
y = 5
Answer: 12 cups of salad blend are in the resulting mixture
Explanation:
Since we have given that
4 cups of a salad blend contains 40% spinach
Using mixture allegation method, we get that
8 cups of a salad blend contains 55% spinach as shown in the figure below.
Now, we need to find the number of cups of salad in the resulting mixture,

Hence, 12 cups of salad blend are in the resulting mixture .
Answer:
- The lowest value of the confidence interval is 0.5262 or 52.62%
- The highest value of the confidence interval is 0.5538 or 55.38%
Step-by-step explanation:
Here you estimate the proportion of people in the population that said did not have children under 18 living at home.It can also be given as a percentage.
The general expression to apply here is;

where ;
p=sample proportion
n=sample size
z*=value of z* from the standard normal distribution for 95% confidence level
Given;
n=5000
<u>Find p</u>
From the question 54% of people chosen said they did not have children under 18 living at home

<u>To calculate the 95% confidence interval, follow the steps below;</u>
- Find the value of z* from the z*-value table
The value of z* from the table is 1.96
- calculate the sample proportion p
The value of p=0.54 as calculated above

Divide the value of p(1-p) with the sample size, n

- Find the square-root of p(1-p)/n

Here multiply the square-root of p(1-p)/n by the z*

The 95% confidence interval for the lower end value is p-margin of error

The 95% confidence interval for the upper end value is p+margin of error

Answer:
5 cubes
Step-by-step explanation:
15/3=5