1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crank
3 years ago
15

To find the quotient of 3 divided by 1/6 multiply 3 by

Mathematics
2 answers:
Olenka [21]3 years ago
4 0

Answer:1.5

Step-by-step explanation:

gayaneshka [121]3 years ago
3 0

Answer:

6

Step-by-s6tep explanation:

You might be interested in
PLEASE HELP! ANSWER NEEDED ASAP!!!<br> <img src="https://tex.z-dn.net/?f=%5Cint%5Climits%20x%5E3%20%28x-%20%5Csqrt%7Bx%7D%20%2B2
77julia77 [94]

fx ^{5} d - fx ^{4 \sqrt{x + 2d} } \\

3 0
3 years ago
An article suggests that a poisson process can be used to represent the occurrence of structural loads over time. suppose the me
kirill115 [55]

Answer:

a) \lambda_1 = 2*2 = 4

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

X(2) \sim Poi (4)

And the expected value is E(X) = \lambda =4

So we expect 4 number of loads in the 2 year period.

b) P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]

P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]

And we got: P(X(2) >6) =1-0.889=0.111

c)  e^{-2t} \leq 2

We can apply natural log in both sides and we got:

-2t \leq ln(0.2)

If we multiply by -1 both sides of the inequality we have:

2t \geq -ln(0.2)

And if we divide both sides by 2 we got:

t \geq \frac{-ln(0.2)}{2}

t \geq 0.8047

And then we can conclude that the time period with any load would be 0.8047 years.

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution"

Solution to the problem

Let X our random variable who represent the "occurrence of structural loads over time"

For this case we have the value for the mean given \mu = 0.5 and we can solve for the parameter \lambda like this:

\frac{1}{\lambda} = 0.5

\lambda =2

So then X(t) \sim Poi (\lambda t)

X follows a Poisson process

Part a

For this case since we are interested in the number of loads in a 2 year period the new rate would be given by:

\lambda_1 = 2*2 = 4

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

X(2) \sim Poi (4)

And the expected value is E(X) = \lambda =4

So we expect 4 number of loads in the 2 year period.

Part b

For this case we want the following probability:

P(X(2) >6)

And we can use the complement rule like this

P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]

And we can solve this like this using the masss function:

P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]

And we got: P(X(2) >6) =1-0.889=0.111

Part c

For this case we know that the arrival time follows an exponential distribution and let T the random variable:

T \sim Exp(\lambda=2)

The probability of no arrival during a period of duration t is given by:

f(T) = e^{-\lambda t}

And we want to find a value of t who satisfy this:

e^{-2t} \leq 2

We can apply natural log in both sides and we got:

-2t \leq ln(0.2)

If we multiply by -1 both sides of the inequality we have:

2t \geq -ln(0.2)

And if we divide both sides by 2 we got:

t \geq \frac{-ln(0.2)}{2}

t \geq 0.8047

And then we can conclude that the time period with any load would be 0.8047 years.

3 0
3 years ago
Maya ran a 100-yd sprint. How many feet did she sprint? I think the answer is 33.3 but i just wanted to clarify?
nydimaria [60]
Yeah it’s 33.3 because there 3 feet in a yard and 100 divided by 3 is 33.3 repeating.
6 0
3 years ago
What is the value of 3-(-2)?
Lostsunrise [7]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The two triangles at right are congruent. What is the perimeter of each? A 4 ft 5 ft 5 ft 6 ft​
dlinn [17]
Hey yaal its 36446473
7 0
3 years ago
Other questions:
  • For the feasibility region shown below, find the maximum value of the function P=3x+2y.
    5·2 answers
  • Write n+5n=______ in simplest form.
    12·2 answers
  • linda thinks of a two digit number. the sum of the digits is 8. if she reverses the digits, the new number is 26 greater than he
    7·1 answer
  • Need help with this please
    13·1 answer
  • Pls help will award most brainliest (this is due today)
    12·1 answer
  • My last question on the pre test someone help lol
    10·1 answer
  • Help Me Please <br> I need to do this for school
    14·2 answers
  • Which of the following situations could be described by the equation y = 120 - 25x?
    11·1 answer
  • The net of an isosceles triangular prism is shown. What is the surface area, in square units, of the triangular prism.
    9·2 answers
  • Help pls iready math equation
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!