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2 years ago

Graph (x+2/3)^2+(y-1/2)^2=1

Mathematics

1 answer:

Basile [38]2 years ago

5 0

3.22222222222222222222222222222222222222222222222

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HELP ME solve for X

Tanya [424]

Answer:

203/11x

Step-by-explanation: I am soo very sorry gave you the wrong answer before but going over it I see it is 203/11x

8 0

2 years ago

A cylinder has a radius of 40 ft and a height of 17 ft. What is the exact surface area of the cylinder?

Georgia [21]

we know that

surface area of the cylinder=2*{area of the base}+perimeter of base*height

area of the base=pi*r²

r=40 ft

Area of base=pi*40²

Area of the base=1600*pi ft²

Perimeter of the base=2*pi*r

Perimeter of the base=2*pi*40

Perimeter of the base=80*pi ft

surface area of the cylinder=2*1600*pi+80*pi*17

surface area=4560*pi ft²

therefore

the answer is the option

4560π ft2

8 0

2 years ago

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The Chinese system presented in the text has symbols for 1 through 9, and also for 10, 100, and 1000. What is the greatest num

Naddika [18.5K]

To get the biggest possible number, use all the symbols at once. 1000+100+10+9+8+7+6+5+4+3+2+1=what?

4 0

2 years ago

A study found that a 95% confidence interval for the mean μ of a particular population was computed from a random sample of 1200

kotykmax [81]

Answer:

95% confidence interval for the mean μ is (6,14)

The Population mean μ lies between ( 6, 14 )

Step-by-step explanation:

Explanation:-

Given random sample 'n' = 1200

95% confidence interval for the mean μ is determined by

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$

Level of significance = 95% 0r 0.05

Z₀.₀₅ = 1.96

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$ = 10 ± 4

Mean of the small sample = 10

95% of confidence intervals are

( 10 ±4 )

( 10 -4 , 10+4)

( 6 , 14 )

95% confidence interval for the mean μ lies between ( 6, 14 )

8 0

2 years ago

For the right triangle shown, the lengths of two sides are given. find the third side. leave your answer in simplified, radical

lisov135 [29]

If c is the hypotenuse and b is the leg, then the third side (a):
$a= \sqrt{c^2-b^2}= \sqrt{16^2-9^2}= \sqrt{256-81}= \sqrt{175}=5 \sqrt{7}$

If b and с are legs, then hypotenuse (a):
$a= \sqrt{b^2+c^2}= \sqrt{9^2+16^2}= \sqrt{81+256}= \sqrt{337}$

3 0

2 years ago

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