Graph (x+2/3)^2+(y-1/2)^2=1
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False; consider as a counterexample the function <em>f</em> : ℝ→ℝ defined by
Clearly <em>f</em> approaches -3 as <em>x</em> gets closer to -2, but neither limit from either side is equal to the function's value at <em>x</em> = 2 (that is, -3 ≠ 0), so <em>f</em> is not continuous.
