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Fiesta28 [93]
3 years ago
5

Deon is going to watch a movie in his collection. He has 10 action movies, 5 comedies, and 8 dramas. He will randomly select one

movie. What is the probability that the movie he selects is not a drama?
Mathematics
1 answer:
nadezda [96]3 years ago
8 0

Answer:

the probability that it is not a drama movie is 15/23

Step-by-step explanation:

To calculate the probability we have to make the number of favorable events divided the number of possible events

number of possible events = x

to calculate it we add all the movies

x = 10 + 5 + 8

x = 23

number of favorable events = y

to calculate it we subtract the drama movies from the total of movies

y = x - 8

y = 23 - 8

y = 15

now we divide 15 by 23 and we get the probability

15/23

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Find the mode of 3, 6, 4, 3, 2, 4, 7, 8, 6, 3, 9
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3 is the mode because it appears most often.

Step-by-step explanation:

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A group of researchers wants to know whether men are more likely than women to contract a novel coronavirus. They surveyed two r
olasank [31]

Answer:

Test statistic Z= 0.13008 < 1.96 at 0.10 level of significance

null hypothesis is accepted

There is no difference proportion of positive tests among men is different from the proportion of positive tests among women

Step-by-step explanation:

<em>Step(I)</em>:-

Given surveyed two random samples of 390 men and 360 women who were tested

first sample proportion

                    p_{1} = \frac{360}{390} = 0.9230

second sample proportion

                  p_{2} = \frac{47}{52} = 0.9038

Step(ii):-

Null hypothesis : H₀ : There is no difference  proportion of positive tests among men is different from the proportion of positive tests among women

Alternative Hypothesis:-

There is difference between proportion of positive tests among men is different from the proportion of positive tests among women

 

Z = \frac{p_{1}- p_{2} }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} }  } }

where

          P = \frac{n_{1}p_{1} +n_{2}  p_{2} }{n_{1}+n_{2}  }

         P =  0.920

Z= \frac{0.9230-0.9038}{\sqrt{0.920 X0.08(\frac{1}{390}+\frac{1}{52}  } )}

Test statistic Z =  0.13008

Level of significance = 0.10

The critical value Z₀.₁₀ = 1.645

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Null hypothesis is accepted

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7 0
3 years ago
Write 0.216 as a rational number in lowest terms
lozanna [386]

Answer:

=\frac{27}{125}

Step-by-step explanation:

0.216

\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}

\mathrm{There\:are\:}3\mathrm{\:digits\:to\:the\:right\:of\:the\:decimal\:point,\:therefore\:multiply\:and\:divide\:by\:}1000

=\frac{0.216\cdot \:1000}{1000}

=\frac{216}{1000}

216,\:1000

\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3

2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

\mathrm{The\:prime\:factors\:common\:to\:}216,\:1000\mathrm{\:are\:}

=2\cdot \:2\cdot \:2

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8

=8

=\frac{8\cdot \:27}{8\cdot \:125}

\mathrm{Cancel\:the\:common\:factor:}\:8

=\frac{27}{125}

Hence, the correct answer is =\frac{27}{125}

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