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2 years ago

15

A board game uses a bag of 105 lettered tiles. You randomly choose a tile and return it to the bag. The table shows the number o

f vowels and the number of consonants after 50 draws. Predict the number of vowels in the bag.
This is what the table says:

Vowels Consonants
18 32

1 answer:

maw [93]2 years ago

3 0

Answer:

38

Step-by-step explanation:

thats the answer

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The sum of two consecutive even integers is 122. what are the integers?

Volgvan

Answer:

If the numbers were the same, they'd both be 61

So, try 60 and 62.

x + x+2 = 122

2x = 120

x = 60

Hope that helps!

4 0

2 years ago

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What are the coordinates of the midpoint of the line segment with the endpoints (2,-5) and (8,3)

Papessa [141]

Midpoint Formula: $(\frac{x_2+x_1}{2} ,\frac{y_2+y_1}{2} )$

Plug the coordinates into the midpoint formula and solve as such:

$(\frac{2+8}{2} ,\frac{-5+3}{2} )\\\\(\frac{10}{2} ,\frac{-2}{2} )\\\\(5,-1)$

<u>Your midpoint is (5,-1).</u>

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2 years ago

The dimensin of a rectangular garden are 12 1/2 feet by 16 3/4 feet. If 1 5/8 feet is added to all the sides,find the new dimens

choli [55]

Answer:

14 1/8 feet by 18 3/8.

Step-by-step explanation:

I took 1 5/8 feet and added it to both...

8 0

2 years ago

the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai

Blababa [14]

Let $X$ be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

$P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10$

where $Z$ follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

$P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)$

where $F_Z(z)=P(Z\le z)$ denotes the CDF of $Z$ , and $F_Z^{-1}$ denotes the inverse CDF. We have

$z_1=F_Z^{-1}(0.90)\approx1.2816$

Similarly, because 20% of students obtain less than 40 marks, we have

$P(X$

so that

$P(Z$

Then $\mu,\sigma$ are such that

$\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma$

$\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma$

and we find

$\mu\approx53.8739,\sigma\approx16.4848$

3 0

3 years ago

xeze [42]

Answer:

x=27, y=18

Step-by-step explanation:

Angle CB is 128, which means angle AC is 72. We can confirm angle O is also 72, since the lines are straight. Angle AM is 27, because AN is a right angle. 63+72+27= 162 180-162=18 Angle ND is 18.

6 0

3 years ago

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