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kvasek [131]
2 years ago
5

Solve each equation, if possible. Write irrational numbers in simplest radical form. Describe the strategy you used to get your

solution and tell why you chose that strategy.
a. x² +4 =0
b. x²^2 -6x +1=0
Mathematics
2 answers:
fomenos2 years ago
4 0
For the answer to the question above, I'll provide my solutions below.
x² + 4 = 0
<span>     - 4  - 4
</span>      x² = -4
       x = +2i

x² - 6x + 1 = 0
x = -(-6) +/- √((-6)² - 4(1)(1))
                       2(1)
x = 6 +/- √(36 - 4)
                 2
x = <span>6 +/- √(32)
</span>             2
x = <span>6 +/- 2√(2)
</span>             2
x = 3 + √(2)
x = 3 + √(2)    x = 3 - √(2)
I hope this helps.
schepotkina [342]2 years ago
4 0
Hello there.
<span>
Solve each equation, if possible. Write irrational numbers in simplest radical form. Describe the strategy you used to get your solution and tell why you chose that strategy.
</span>
x = 3 + √(2)    x = 3 - √(2)

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