PLEASE HELP, SOLVE THIS PROBLEM AND GIVE ME THE ANSWER!!!

The perimeter of a rectangular painting is 362 CM if the length of the painting is 97 centimeters what is its width

pochemuha

Answer:

84

Step-by-step explanation:

97+97=194 because a rectangle has 2 long sides.

362-194=168

168/2=84

Width=84 cm

4 0

2 years ago

What is the value of x?

Mnenie [13.5K]

Hello! i'm not quite sure if this is the answer, but i believe it would be 76. I'm not that good with angles, but i'm trying my best to help! I hope the answer helped you! i'm sorry if i get it wrong though. If you have any questions, pm me! thanks!

6 0

2 years ago

Identify the ordered pair that represents the vector from a(-9,9) to b(7,3) and the magnitude of ab.

sveta [45]

Answer:

Answers below

Step-by-step explanation:

1. Order pair method

[(x2-x1) , (y2-y1)] = b-a = [(7--9) , (3-9)] = (16,-6)

2. Magnitude

|v| = $\sqrt{16^2+-6^2}$

v = |17.088|

7 0

2 years ago

Read 2 more answers

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

4 0

2 years ago

The data below represents the number of minutes Jake and Sarah spent doing chores

hichkok12 [17]

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The median number of minutes for Jake and Sarah are equal, but the mean numbers are different.

-

For this, you never said the choices, but I’ve done this before, so I’m going to use the answer choices I had, and hopefully they are right.

Our choices are -

• The median number of minutes for Jake is higher than the median number of minutes for Sarah.

• The mean number of minutes for Sarah is higher than the mean number of minutes for Jake.

• The mean number of minutes for Jake and Sarah are equal, but the median number of minutes are different.

• The median number of minutes for Jake and Sarah are equal, but the mean number of minutes are different.

————————

So to answer the question, we neee to find the median and mean for each data set, so -

Jack = [90 median] [89.6 mean]
Sarah = [90 median] [89.5 mean]

We can clearly see the median for both is 90, so we can eliminate all the choices that say they are unequal.

We can also see that Jack has a higher mean (89.6) compared to Sarah (89.5).

We can eliminate all the choices that don’t imply that too.

That leaves us with -

• The median number of minutes for Jake and Sarah are equal, but the mean number of minutes are different.

8 0

2 years ago