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Afina-wow [57]
3 years ago
6

Solve for EG. A) 18 B) 12 9 D) 6​

Mathematics
2 answers:
nikdorinn [45]3 years ago
4 0

Answer:

a

Step-by-step explanation:

viktelen [127]3 years ago
4 0

Answer:

D

Step-by-step explanation:

BRAINLIEST PLEASE

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If someone understands this please help
katrin [286]

Answer:

A= 4

B= 4

C= -1

D= 4

E= -1

F= 4

G= -1

Step-by-step explanation:

The expected value equation is the probability of something happening multiplied by the amount of times it happens. In this case you have four equal sized sections, so you have a one in four chance to land in any of these sections. A, B, D, and F represent the four for this one in four chance. C, E, and G represent the amount of points you get when you land on those sections, in this case -1

3 0
3 years ago
Which is the correct answer?? I have 5 mins left to finish this pls help
NeX [460]

Answer:

25.3

Step-by-step explanation:

I just put it in my calculator.

5 0
3 years ago
Which of these is a statistical question? I accidentally clicked an clicked an answer, but I want to know which one is the right
sasho [114]

Step-by-step explanation:

I think A is the answer to your question

7 0
3 years ago
On a map, 2 inches represents 60 miles. What part of an inch represents 12 miles? Please show how you get you answer.
e-lub [12.9K]
C: 2/5 inches is your answer 

if 2 inches are 60 miles then 12 miles is a fifth of 2 inches.
8 0
3 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
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