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Afina-wow [57]
3 years ago
6

Solve for EG. A) 18 B) 12 9 D) 6​

Mathematics
2 answers:
nikdorinn [45]3 years ago
4 0

Answer:

a

Step-by-step explanation:

viktelen [127]3 years ago
4 0

Answer:

D

Step-by-step explanation:

BRAINLIEST PLEASE

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The sum of a number 1/6 of that number 2 1/2 of that number and seven is 12 1/2 find the number
Zigmanuir [339]

Answer:

Step-by-step explanation:

x = the number

x + 1/6x + 2 1/2x + 7 = 12 1/2

3 + (1/6 + 1/2)x = 12 1/2 - 7

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What does the fundamental theorem of algebra illustrate?
UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form ax^{2}+bx +c=0

Its roots are \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Here the given equation is 2x^{2}-4x-1 = 0

a = 2

b = -4

c = -1

If the roots are x_{1} and x_{2}, then

x_{1} = \frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                       = \frac{4 +\sqrt{24}}{4}

                       = \frac{2+\sqrt{6} }{2}

x_{2} = \frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                        = \frac{4 +\sqrt{8}}{4}

                        = \frac{2-\sqrt{6} }{2}

These are the two roots of the equation.

6 0
3 years ago
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