Question

One integer is 1/3 times another. The sum of their squares is 90. What are the two integer?

Answer 1

Answer:

Hence, the two integers could be:

                   3 and 9

                        0R

                   -3 and -9

Step-by-step explanation:

Let the two integers be denoted by a and b.

It is given that:

One integer is 1/3 times another.

i.e. let

$a=\dfrac{1}{3}b$

i.e.

$b=3a$

Also,

The sum of their squares is 90.

i.e.

$a^2+b^2=90\\\\i.e.\\\\a^2+(3a)^2=90\\\\i.e.\\\\a^2+9a^2=90\\\\i.e.\\\\10a^2=90\\\\i.e.\\\\a^2=9\\\\i.e.\\\\a=\pm 3$

Hence, when a=3 we have:

$b=9$

and when,

$a=-3$

then b=-9