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3 years ago

What is more ways to solve this problem. 3• + (-5)=19

Mathematics

1 answer:

marin [14]3 years ago

8 0

I will ha em your answer in 15 minutes

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The length of a rectangular pool is 20 feet and the width is 15 feet. The

Ray Of Light [21]

Answer:

$255

Step-by-step explanation:

As, the area of the pool bottom = length x breath

= 20 x 15 = 300 square foot

So for painting

Per square foot = $0.85

So for 300 square foot = $0.85 x 300

= $255

5 0

2 years ago

What is 0.63 repeating as a fraction in simplest form

Sergeeva-Olga [200]

The simplest form is 63/100 <span />

3 0

3 years ago

Hi! Please help me, will mark brainliest!

PIT_PIT [208]

Answer:

p(t) = 0 for t = 1

p(t) = 1 for t = 1/8 = 8^-1

Step-by-step explanation:

the graph you will have to do yourself.

just go there and type in

$- log_{8}(x)$

well, don't type "log" in letters.

you start by typing the "-" sign, and then you need to look up the functions by clicking on the "funcs" button and look for the log functions .

pick the

$log_{a}$

option. and then simply enter 8 as the first parameter in the {} brackets and x as the second in the () brackets.

and then you see.

any logarithm is 0 for x (or t) = 1.

because any a⁰ = 1.

and the logarithm gives you that exponent of the base number that leads to the given x value.

in other words : a logarithm is the inverse function of an exponential function.

the exponential function is

y = a^x

and the logarithm then determines

$x = log_{a}(y)$

that is all.

and

$- log_{8}(x) = 1$

means that the logarithm itself delivered -1.

and 8^-1 = 1/8

so, p(t) = 1 for t = 1/8

5 0

1 year ago

G I need help with this too

Bogdan [553]

Step-by-step explanation:

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7 0

2 years ago

Charlie's garage has a rectangular floor space. Its length is 3 times its width. Charlie extends the width of his garage to 6 m,

MAXImum [283]

Answer:

The percentage change is 140%

Step-by-step explanation:

Given

$L= 3W_1$ ---- initial dimension

$W_2 = 6m$ --- new width

$A_2 = 45m^2$ --- new dimension

Required

The percentage increment

The length remains constant because only the width is extended.

The new area is:

$Area =Length * Width$

$A_2=L * W_2$

Make L the subject

$L = \frac{A_2}{ W_2}$

Substitute values for A and W

$L = \frac{45m^2}{6m}$

$L = \frac{45m}{6}$

$L = 7.5m$ --- this is the length of the garden

Calculate the initial width:

$L= 3W_1$

Make W1 the subject

$W_1 = \frac{1}{3} * L$

$W_1 = \frac{1}{3} * 7.5$

$W_1 = 2.5$

So, the initial area is:

$A_1 = L_1 * W_1$

$A_1 = 2.5 * 7.5$

$A_1 = 18.75$

The percentage change in area is:

$\%A = \frac{A_2 - A_1}{A_1}$

$\%A = \frac{45 - 18.75}{18.75}$

$\%A = \frac{26.25}{18.75}$

$\%A = 1.4$

Express as percentage

$\%A = 1.4*100\%$

$\%A = 140\%$

4 0

3 years ago