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yuradex [85]
4 years ago
9

B2≤4 What is the solution to the inequality? b≥8 b≤8 b≤2 b≥2

Mathematics
2 answers:
Allisa [31]4 years ago
8 0
The solution is the third one:
b≤2
telo118 [61]4 years ago
8 0
Should be b is less than or equal to 2.

b2 < 4 divide both sides by 2 gives you your answer. Just be sure to put the line under to show the equals b < 2
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Let f(x)= x(2x-3)/(x+2)x. Find the domain, vertical and horizontal asymptote
Reptile [31]

Step-by-step explanation:

Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues

Here, we have

\frac{x(2x - 3)}{(x + 2)x}

First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.

Since, we don't want x to be 0,

We have a removable discontinuity at x=0

Now, we have

\frac{2x - 3}{x + 2}

We don't want the denomiator be zero because we can't divide by zero.

so

x + 2 = 0

x =  - 2

So our domain is

All Real Numbers except-2 and 0.

The vertical asymptors is x=-2.

To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of

The leading coeffixent of the numerator/ the leading coefficent of the denomiator.

So that becomes

\frac{2}{1}  = 2

So we have a horinzontal asymptofe of 2

7 0
3 years ago
Which rule yields the dilation of the figure STUV centered at the origin?
Stels [109]

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Answer:

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marysya [2.9K]
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Please help with #12
ExtremeBDS [4]

Answer:

a. 1 1/8 b. 8/9

Step-by-step explanation:

You can set this up as a proportion to solve.  For part a. we know that 2/3 of the road is 3/4 mile long.  2/3 + 1/3 = the whole road, so we need how many miles of the road is 1/3 its length.  Set up the proportion like this:

\frac{\frac{2}{3} }{\frac{3}{4} } =\frac{\frac{1}{3} }{x}

Cross multiplying gives you:

\frac{2}{3}x=\frac{1}{3}*\frac{3}{4}

The 3's on the right cancel out nicely, leaving you with

\frac{2}{3}x=\frac{1}{4}

To solve for x, multiply both sides by 3/2:

\frac{3}{2}*\frac{2}{3}x=\frac{1}{4}*\frac{3}{2} gives you

x=\frac{3}{8}

That means that the road is still missing 3/8 of a mile til it's finished.  The length of the road is found by adding the 3/4 to the 3/8:

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So the road is a total of 1 1/8 miles long.

For b. we need to find out how much of 1 1/8 is 1 mile:

1 mile = x * 9/8 and

x = 8/9.  When 1 mile of the road is completed, that is 8/9 of the total length of the road completed.

8 0
3 years ago
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