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4 years ago

Two similar prisms have heights 4 cm and 10cm what is the ratio of their surface areas

1 answer:

4 0

Let k be the scale factor relating two similar prisms $P_{1}$ and $P_{2}$ , such that for corresponding parts of prisms $P_{1}$ and $P_{2}$ (for heights, in particular) we have $k= \frac{height\ of \ P_{1} }{height \ of\ P_{2} }$ . In our case $k= \frac{4}{10} = \frac{2}{5}$ .
For surfaces area we have $\frac{Surface \ area \ of \ P_{1} }{Surface \ area \ of \ P_{2}} = k^{2} =( \frac{2}{5} )^{2}= \frac{4}{25}$ .
So, the right answer is 4:25 (choice B)

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Montella selling roses for four dollars each to raise money for a local charity if you spends 184 to buy the flowers roses Xmas

Dmitry_Shevchenko [17]

Complete question :

Montel is selling roses for $4 each to raise money for a local charity. If he spend $184 to buy the flowers, how many roses ,x, must Montel sell to make a profit of at least $360

Answer:

x > 136

Step-by-step explanation:

To make a profit of $360

Selling price per rose = $4

Amount spent on roses = $184

To male a profit of at least $360

The total revenue made from rose sale must be :

Cost price + profit made

$184 + $360 = $544

To make a profit of at least, $360, them he must sell at least :

$544 / selling price

$544 / $4

= 136

x > 136

8 0

3 years ago

Answer the last one please answer fast

Oduvanchick [21]

Answer:

Step-by-step explanation:

Put the equation in the form ax+by+c=0:

$y\sqrt{3} =8x+\sqrt{3} \\=>8x-\sqrt{3} y+\sqrt{3} =0$

Check the solutions:

$(0,-1)$ :

$8(0)-\sqrt{3} (-1)+\sqrt{3} =2\sqrt{3}$

So this is not a solution.

( $(\sqrt{3} ,9)$ :

$8\sqrt{3} -9\sqrt{3} +\sqrt{3} =0$

So this is a solution

4 0

3 years ago

The equation of three lines are given below

kotykmax [81]

Answer:

The line 2 and Line 3 are perpendicular to each others

But There is no relation between Line 1 and Line 2 , Line 1 and Line 3

Step-by-step explanation:

Given as :

The three line equation is

Line 1 : 2 y = 5 x + 6

Line 2 : y = $\frac{2}{5}$ x - 1

Line 3 : 10 x + 4 y = - 6

Now, The standard equation of line is

y = m x + c

where m is the slope of line

And c is the y intercept

So, From Line 1

2 y = 5 x + 6

or , y = $\frac{5}{2}$ x + $\frac{6}{2}$

I.e y = $\frac{5}{2}$ x + 3

So, slope of this line = $m_1$ = $\frac{5}{2}$

Again , From Line 2

y = $\frac{2}{5}$ x - 1

So, slope of this line = $m_2$ = $\frac{2}{5}$

Similarly , From Line 3

10 x + 4 y = - 6

I.e 4 y = - 6 - 10 x

or, y = - $\frac{6}{4}$ - $\frac{10}{4}$ x

I.e y = - $\frac{5}{2}$ x - $\frac{6}{4}$

So, Slope of this line = $m_3$ = - $\frac{5}{2}$

Now, If the lines are parallel , then the slope of the lines are equal

And If the lines are perpendicular , then the product of the slopes of the lines = - 1

Now, From given lines

$m_2$ × $m_3$ = $\frac{2}{5}$ × ( - $\frac{5}{2}$ )

I.e $m_2$ × $m_3$ = - 1

So, The line 2 and Line 3 are perpendicular to each others

But There is no relation between Line 1 and Line 2 , Line 1 and Line 3

Hence The line 2 and Line 3 are perpendicular to each others

But There is no relation between Line 1 and Line 2 , Line 1 and Line 3 Answer

6 0

4 years ago

Group of answer choices 33 50 52 55

vodomira [7]

Answer:

Step-by-step explanation:

ik its ritgh

4 0

3 years ago

8.5(4+3h)-h simplified

nikklg [1K]

Answer:

$34+24.5h$

Step-by-step explanation:

$8.5(4+3h)-h\\\\=8.5(4)+8.5(3h)-h\\\\=34+25.5h-h\\\\=34+24.5h$

4 0

3 years ago

Read 2 more answers