Answer:
The intensity of the earthquake in Chile was about 16 times the intensity of the earthquake in Haiti.
Step-by-step explanation:
Given:
magnitude of earthquake in Chile = 8.2
magnitude of earthquake in Haiti = 7.0
To find:
Compare the intensities of the two earthquakes
Solution:
The magnitude R of earthquake is measured by R = log I
R is basically the magnitude on Richter scale
I is the intensity of shock wave
For Chile:
given magnitude R of earthquake in Chile = 8.2
R = log I
8.2 = log I
We know that:
is equivalent to: 
8.2 = log I becomes:
So the intensity of the earthquake in Chile:
For Haiti:
R = log I
7.0 = log I
We know that:
is equivalent to:
7.0 = log I becomes:
So the intensity of the earthquake in Haiti:
Compare the two intensities :
= 
= 
= 15.848932
Round to the nearest whole number:
16
Hence former earthquake was 16 times as intense as the latter earthquake.
Another way to compare intensities:
Find the ratio of the intensities i.e.
- 
= 8.2 - 7.0
= 1.2
Convert this logarithmic equation to an exponential equation
= 1.2
=
Hence
= 16
We have been given the function 
Now, we can see that in the transformed function 
, we have added 3 in the x.
Whenever we add/subtract some constant in the x, then the function gets translated to either left or right.
We know that if f(x) is a parent function and if we add a constant c then the function gets shift to c unit left.
Therefore, the given graph will get shifted 3 units left.
D is the correct option.
Translate each point of the graph of h(x) 3 units left.
a and b are the two leg sides
c is the longest side.
a^2+b^2=c^2
a=x
b=9
c=11
a=c-b
11 squared is 121
9 squared is 81
121-81=40
The square root of 40, rounded to the nearest hundredth, is 6.32
Answer:
9 cookies in her original handful
Step-by-step explanation:
3 times 4 equals 12
12-3=9
Answer:
• multiplied by 4p: (x -h)² +4pk = 0
• zeros for k > 0: none
• zeros for k = 0: one
• zeros for k < 0: two
Step-by-step explanation:
a) Multiplying by 4p removes the 1/(4p) factor from the squared term, but adds a factor of 4p to the k term. (It has no effect on the subsequent questions or answers, so we wonder why we're doing this.) The result is ...
(x -h)² +4pk = 0
__
b) The value of k is the vertical location of the vertex of the parabola with respect to the x-axis. The parabola opens upward, so for k > 0, the parabola does not cross the x-axis, and the number of real zeros is zero. (There are two complex zeros.)
__
c) As in part b, the value of k defines the vertex location. When it is zero, the vertex of the parabola is on the x-axis, so there is one real zero (It is considered to have multiplicity 2.)
__
d) As in part b, the value of k defines the vertex location. When it is negative, the vertex of the parabola is below the x-axis. Since the parabola opens upward, both branches will cross the x-axis, resulting in two real zeros.
_____
The attached graph shows a parabola with p=1/4 and h=2. The values shown for k are +1, 0, and -1. The coordinates of the real zeros are shown.
