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Vlad1618 [11]
3 years ago
7

How was pre-image ABC transformed to

Mathematics
2 answers:
AlexFokin [52]3 years ago
5 0

Answer:

the answer is D-reflection over line BC

Step-by-step explanation:

kumpel [21]3 years ago
4 0

Answer:

It's answer D.

Step-by-step explanation:

It's like if you were to turn a page to a book or unfold something you would turn it from down the middle just like how they copied it down the middle here (also I have an azva student I took the test and it was correct.)

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The volume of Mikes rectangular lunch box is 240 cubic inches. The lunchbox is 3 inches deep and its length is 2 inches more the
allochka39001 [22]

Answer:

8 inches

Step-by-step explanation:

You first divide 240 by 3 which is 80

Then you find what number is 2 less than the other number that is you multiplied together you get 80

And we know that 8 × 10 = 80

There for the :-

Width is 8 in

Length is 10 in

Hight is 3 in

The proof is if you multiply all of them you have to get 240

And if you multiply 8, 10, and 3 you get 240

6 0
2 years ago
What is the perimeter of 6ft and 4ft​
Viktor [21]

it is 20 because you have to do 4+4+6+6

3 0
3 years ago
Read 2 more answers
Joseph just changed his cable television plan to include on demand movies for $2.95 each. The charge for the basic cable passage
mel-nik [20]
x-number\ of\ movies\\\\24.95+2.95x=39.7\\2.95x=39.7-24.95\\2.95x=14.75\ \ \ \ \ \ |:2.95\\x=5\\\\He\ watched\ 5\ movies.
7 0
3 years ago
The radius of a circle is 8 miles. What is the area of a sector bounded by a 135° arc?
Jlenok [28]

Answer:

13.5* pi sq miles

Step-by-step explanation:

7 0
3 years ago
The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill
lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

A = Height * Base

Where

Height = 10ft --- Height of the pillar

Base = 3ft --- Base of the pillar

So:

A = 10ft * 3ft

A = 30ft^2

The area of the 4 sides of the pillar is:

A_2 = 4 * A --- i.e. 4 multiplied by the area of 1 side

A_2 = 4 * 30ft^2

A_2 = 120ft^2

The area of the 2 pillars is:

Area_1 = 2 * A_2 --- i.e. 2 multiplied by the area if 1

Area_1 = 2 * 120ft^2

Area_1 = 240ft^2

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}

Where:

h = 2 -- the height

l = w = 3 --- the base of the pillar is the length and width of the pyramid.

So, we have:

Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}

Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}

Area = 3\sqrt{5} + 3\sqrt{5}

Area = 6\sqrt{5}

For the two pyramids, the area is:

Area_2 = 2 * 6\sqrt 5 -- 2 multiplied by area of 1

Area_2 = 12\sqrt 5

Area_2 = 26.8

So, the total area to be painted is:

Total = Area_1 + Area_2 --- the sum of the area of the pillars and the pyramids

Total = 240+26.8

Total = 266.8ft^2

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

Cost = 80 * 266.8

Cost = Rs.21344

Read more at:

brainly.com/question/14320476

7 0
3 years ago
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