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Arada [10]
3 years ago
8

P Casey is reading a book for a book report. At 3:30 P.M., he started reading where he had left off the day before. At 5:30 P.M.

he was on page 160. At 8:00 P.M. he was on page 280. If reading the book is modeled by a linear function, what page did Casey start on at 3:30 P.M.?
Mathematics
2 answers:
Blababa [14]3 years ago
7 0
If you would like to know the page that Casey start on at 3:30 P.M., you can calculate this using the following steps:

8:00 P.M. - <span>5:30 P.M. = 2:30
280 - 160 = 120 pages

</span><span>5:30 P.M. - 3:30 P.M. = 2:00

2:30 = 150 minutes ... 120 pages
2:00 = 120 minutes ... x pages = ?

150 * x = 120 * 120
x = 120 * 120 / 150
x = 96 pages

160 pages - 96 pages = 64

Casey started on page 64.</span>
Tema [17]3 years ago
4 0
Given:
3:30 - 5:30 = page 160
5:30 - 8:00 = page 280

280 - 160 = 120
8:00 - 5:30 = 2.5 hours or 5 half hours 
120 / 5 half hours  =  24 pages every half hour or 30 minutes

3:30 - 5:30 = 2 hours or 4 half hours
24 * 4 = 96 pages

160 - 96 = 64

P Casey was on page 64 at 3:30 p.m.
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ArbitrLikvidat [17]

Answer:

The triangles in figures A , D have an area of 22.5 units²

Step-by-step explanation:

* Lets explain how to solve the problem

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  triangle and h is the height of this base

- The horizontal line has same y-coordinates of its endpoints

- The vertical line has same x-coordinates of its endpoints

- In the Cartesian coordinates the length of any horizontal line is the

 difference between the x-coordinates of its endpoints and the length

 of any vertical line is the difference between the y-coordinates of

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* Lets solve the problem

# Figure A

∵ The vertices of the triangles are (-5 , 0) , (10 , 0) , (-1 , 3)

∵ the end points of its base are (-5 , 0) , (10 , 0)

∵ The base of the triangle = 10 - (-5) = 10 + 5 = 15 units

∵ The height of the triangle is the difference between the

   y-coordinates of its vertex and the y-coordinate of its base

∵ The y-coordinate of the vertex is 3

∵ The y-coordinate of the base is 0

∴ The height of the triangle = 3 - 0 = 3 units

∴ Its A = 1/2 (15)(3) = 22.5 units²

* The triangle in figure A has an area of 22.5 units²

# Figure B

∵ The vertices of the triangles are (-1 , -1) , (-6 , -1) , (-2 , -8)

∵ the end points of its base are (-1 , -1) , (-6 , -1)

∵ The base of the triangle = -1 - (-6) = -1 + 6 = 5 units

∵ The height of the triangle is the difference between the

   y-coordinates of its vertex and the y-coordinate of its base

∵ The y-coordinate of the vertex is -8

∵ The y-coordinate of the base is -1

∴ The height of the triangle = -1 - (-8) = -1 + 8 = 7 units

∴ Its A = 1/2 (5)(7) = 17.5 units²

* The triangle in figure B has an area of 17.5 units²

# Figure C

∵ The vertices of the triangles are (-9 , 2) , (-1 , 2) , (-7 , 8)

∵ the end points of its base are (-9 , 2) , (-1 , 2)

∵ The base of the triangle = -1 - (-9) = -1 + 9 = 8 units

∵ The height of the triangle is the difference between the

   y-coordinates of its vertex and the y-coordinate of its base

∵ The y-coordinate of the vertex is 8

∵ The y-coordinate of the base is 2

∴ The height of the triangle = 8 - 2 = 6 units

∴ Its A = 1/2 (8)(6) = 24 units²

* The triangle in figure C has an area of 24 units²

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∵ The vertices of the triangles are (0 , 0) , (0 , -9) , (5 , -7)

∵ the end points of its base are (0 , 0) , (0 , -9)

∵ The base of the triangle = 0 - (-9) = 0 + 9 = 9 units

∵ The height of the triangle is the difference between the

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∵ The x-coordinate of the vertex is 5

∵ The x-coordinate of the base is 0

∴ The height of the triangle = 5 - 0 = 5 units

∴ Its A = 1/2 (5)(9) = 22.5 units²

* The triangle in figure D has an area of 22.5 units²

∴ The triangles in A , D have an area of 22.5 units²

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