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2 years ago

6

fran found this expression in her cookbook. 1/3 divided by 2.write a scenario that explains the expression and solve

1 answer:

mars1129 [50]2 years ago

4 0

This may help:

There are $\frac{1}{3}$ gallons of lemonade.

Two friends share the lemonade.

What fraction of the lemonade does each friend receive?

To solve you do kcf or keep change flip.

You keep $\frac{1}{3}$ and change division to multiplication.

Then $\frac{2}{1}$ is changed to $\frac{1}{2}$

<span>The answer would be </span> $\frac{1}{6}$

Hope That Helps!

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Which of the following is the correct answer after multiplying both sides of the inequality -x > -3 by -1?

Drupady [299]

Answer:

x < 3

Step-by-step explanation:

When you multipy an inequality by a negative, remember to switch the inequality sign!

-x > -3

(-x)(-1) > (-3)(-1)

x < 3

please give thanks and hit the heart button :)

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2 years ago

Read 2 more answers

Someone plz explain!

ryzh [129]

Answer:

18° and 72°

Step-by-step explanation:

Complimentary angles form 90°

We have an angle (x) 4 times larger than the other (y).

Well actually, a system of equations isn't required, so forget about x and y, just divide 90 by 5. This gives you 18, one of the angle's measurements is 18°. Multiply 18 by 4 and get 72. The other angle's measurement is 72°.

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3 years ago

Which of the following expressions is equivalent to 4^-3?<br><br>

-BARSIC- [3]

Answer:

x(12y+4)

Step-by-step explanation:

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2 years ago

mafiozo [28]

Answer:

$\displaystyle \: \frac{5}{4}$

Step-by-step explanation:

we are given a expression

we are said to solve it using L'Hôpital's Rule

recall, L'Hôpital's Rule:

$\displaystyle \lim _{x \to \: c}( \frac{f(x)}{g(x)} ) = \lim _{x \to \: c} \frac{f ^{'}(x) }{ {g}^{'}(x) }$

it is to say the ' means derivative

our given expression:

$\displaystyle\lim_{ x\to 2}\frac{x^2+x-6}{x^2-4}$

let's apply L'Hôpital's Rule

$\displaystyle\lim_{ x\to 2}\frac{ \dfrac{d}{dx} (x^2+x-6)}{ \dfrac{d}{dx} (x^2-4)}$

some formulas of derivative

$\displaystyle \: \frac{d}{dx} {x}^{n} = {nx}^{n - 1}$

$\displaystyle \: \frac{d}{dx} {x}^{} = 1$

$\displaystyle \: \frac{d}{dx} {c}^{} = 0$

$\sf \displaystyle \: \frac{d}{dx} {f}^{} (x) + {g}^{}(x) = {f}^{'} (x) + {g}^{'}(x)$

use sum derivative formula to simplify:

$\displaystyle\lim_{ x\to 2}\frac{ \dfrac{d}{dx} (x^2)+ \dfrac{d}{dx} (x) + \dfrac{d}{dx}( -6)}{ \dfrac{d}{dx} (x^2) + \dfrac{d}{dx} (-4)}$

simplify using exponents using exponent derivative formula:

$\displaystyle\lim_{ x\to 2}\frac{ 2x+ \dfrac{d}{dx} (x) + \dfrac{d}{dx}( -6)}{ 2x + \dfrac{d}{dx} (-4)}$

use variable derivative formula to simplify variable:

$\displaystyle\lim_{ x\to 2}\frac{ 2x+ 1+ \dfrac{d}{dx}( -6)}{ 2x + \dfrac{d}{dx} (-4)}$

use constant derivative formula to simplify derivative:

$\displaystyle\lim_{ x\to 2}\frac{ 2x+ 1+ 0}{ 2x + 0}$

simplify addition:

$\displaystyle\lim_{ x\to 2}\frac{ 2x+ 1}{ 2x }$

since we are approaching x to 2

we can substitute 2 for x

$\displaystyle\lim_{ x\to 2}\frac{ 2.2+ 1}{ 2.2 }$

simplify multiplication:

$\displaystyle\frac{ 4+ 1}{ 4}$

simplify addition:

$\displaystyle \: \frac{5}{4}$

hence,

$\displaystyle\lim_{ x\to 2}\frac{ \dfrac{d}{dx} (x^2+x-6)}{ \dfrac{d}{dx} (x^2-4)} = \frac{5}{4}$

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3 years ago

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Licemer1 [7]

F^-1 (x)= -x/5 + 4/5 (Answer)

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2 years ago