Simplify (x^2 y^3) (x^4 y^2) a. X^6y^5 b. x^8y^6 c. 2x^8y^6 d. 2x^6y^5
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You can use a tangent:
We have opposite = 17 and adjacent = x.
substitute:
cross multiply
multiply both sides by √3
divide both sides by 3
Use the Pythagorean theorem:
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Other method.
triangle.
The sides are in the ratio
Therefore