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goldfiish [28.3K]

3 years ago

12

The subway sold 439 tickets in one day. It wants to sell that amount each day over the next 13 days. How many tickets does the s

ubway need to sell over the next 13 days?

1 answer:

ss7ja [257]3 years ago

4 0

Answer:

5707 tickets

Step-by-step explanation:

We want to sell 439 tickets each day for the next 13 days

439 * 13 =5707

We need to sell a total of 5707 tickets

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Find the unknown digit to make each statement true <br> 3.59 > 3.5 1 >3.572

Softa [21]

We are given statement 3.59 > 3.5__1 >3.572.

We have a blank space in between 5 and 1 in the middle number given.

Given statement ccan be read as :

3.59 is greater than 3.5__1 is greater than 3.572.

So, we need to check a number that is less than 3.59 but less than 3.572.

The hundredth place of 3.59 number is 9 and

hundredth place of 3.572 number is 7.

So, we need to find a number between 7 and 9.

8 is the number in between 7 and 9.

So, the known digit can be replaced by 8 to make the statement true.

And final statement is 3.59 > 3.581 >3.572.

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2 years ago

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2 years ago

An angle measures 38° more than the measure of its complementary angle. What is the measure of each angle?

seropon [69]

Answer: 38° and 52°

Steps:
x + 38° = 90°
x = 90° - 38°
x = 52°

90° - 52° = 38°

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3 years ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

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3 years ago

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VMariaS [17]

Answer:

For the function $f(x)=4 x-3$ the average rate change from x is equal 1 to x is equal 2 is 4 .

Step-by-step explanation:

A function is given f(x)=4x-3.

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Step 1 of 2

A function f(x)=4 x-3 is given.

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$\begin{aligned}&f(1)=4(1)-3 \\&f(1)=1\end{aligned}$$$$f(1)=1$

Determine the function $f\left(x_{1}\right)$ by putting the value of x is 2 in the given function.

$\begin{aligned}&f(2)=4(2)-3 \\&f(2)=5\end{aligned}$

Step 2 of 2

According to the formula of average rate change of the equation $\frac{\Delta y}{\Delta x}=\frac{f\left(x_{2}\right)-f\left(x_{2}\right)}{x_{2}-x_{1}}$

Substitute the value of $f\left(x_{1}\right)$ with, $f\left(x_{1}\right)$ with $3, x_{2}$ with 2 and $x_{1}$ with 1 .

$\begin{aligned}&\frac{\Delta y}{\Delta x}=\frac{5-1}{1} \\&\frac{\Delta y}{\Delta x}=4\end{aligned}$

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1 year ago