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3 years ago

15

What is the approximate side length of each square

1 answer:

alexandr1967 [171]3 years ago

8 0

Answer: $9\ units$

Step-by-step explanation:

You need to use the following formula for calculate the area of a square:

$A=s^2$

Where "s" is the lenght of any side of the square.

You know that the area of a mural is $81\ units^2$ . Then, you can substitute this area into the formula and solve for "s", in order to find the side lenght of the mural.

Therefore, this is:

$81\ units^2=s^2\\\\s=\sqrt{(81\ units^2)}\\\\s=9\ units$

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3 years ago

If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that

Ivan

Answer:

$\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}$

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• $\sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}$

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

• $\sf\implies cos2A =\dfrac{\sqrt3}{2}$

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

$\sf\implies cos2A = 1 - 2sin^2A$

Therefore , here substituting the value of sinA , we have ,

$\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2$

Simplify the whole square ,

$\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}$

Add the numbers in numerator ,

$\sf\implies cos2A = 1-2\times \dfrac{4-2\sqrt3}{8}$

Multiply it by 2 ,

$\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}$

Take out 2 common from the numerator ,

$\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}$

Simplify ,

$\sf\implies cos2A = 1 -\dfrac{ 2-\sqrt3}{2}$

Subtract the numbers ,

$\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}$

Simplify,

$\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }$

Hence Proved !

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3 years ago

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ira [324]

Answer:

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Step-by-step explanation:

Here, we are tasked with calculating the roaming area that Fido has

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Step-by-step explanation:

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Step-by-step explanation:

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11 months ago