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3 years ago

A hose fills a hot tub at a rate of 2.65 gallons per minute. How many hours will it take to fill a 283 -gallon hot tub?

Mathematics

1 answer:

dsp733 years ago

7 0

Answer:

you need to substitute values on the next form of resolving this problem as follows...

A hose fills up a hot tub at a rate of 3.2 gallons per minute. How many hours will it take to fill a 300 gallon hot tub?

please explain the method of unit conversions as thoroughly as possible.

Solution:

The rate of fill up is, Rate = 3.2 Gallons / minute = 3.2 g/min

The hut tub volume is 300 Gallons

You can set up this problem as follows:

Every 3.2 gallons require 1 minute, How many minutes 300 gallons require?

3.2 g 1min

300 g ? min = (300 gallons x 1min/ 3.2 gallons)=(300/32)min

= 93.75 min

or simply the number minutes is the time required (T) the rate is (R) and the volume is (V)

such that T=V/R= (300g/3.2 g/min)= 93.75 min

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What is 20 percent of 9,500

iVinArrow [24]

Answer:

1900

Step-by-step explanation:

3 0

3 years ago

You are going to roll two dice. Let the variable x = the sum of the numbers rolled. What is the probability that x = 9 ?

Vladimir79 [104]

The first cube can land in any one of 6 ways.
The second cube can land in any one of 6 ways.
Total number of ways that 2 dice can land = (6 x 6) = 36 ways.

For any of these ways, the sum of the numbers rolled is 9 :

3, 6
4, 5
5, 4
6, 3

There are 4 ways to roll a 9, out of a total of 36 ways that
the dice can land. So the probability of rolling a 9 is

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7 0

3 years ago

9.3.2 Listed below are body temperatures from five different subjects measured at 8 AM and again at 12 AM. Find the values of d

kotegsom [21]

Answer:

$\frac{}{d}$ = −0.26

$s_{d}$ = 0.4219

Step-by-step explanation:

Given:

Sample1: 98.1 98.8 97.3 97.5 97.9

Sample2: 98.7 99.4 97.7 97.1 98.0

Sample 1 Sample 2 Difference d

98.1 98.7 -0.6

98.8 99.4 -0.6

97.3 97.7 -0.4

97.5 97.1 0.4

97.9 98.0 -0.1

To find:

Find the values of $\frac{}{d}$ and $s_{d}$

d overbar ( $\frac{}{d}$ ) is the sample mean of the differences which is calculated by dividing the sum of all the values of difference d with the number of values i.e. n = 5

$\frac{}{d}$ = ∑d/n

= (−0.6 −0.6 −0.4 +0.4 −0.1) / 5

= −1.3 / 5

$\frac{}{d}$ = −0.26

s Subscript d is the sample standard deviation of the difference which is calculated as following:

$s_{d}$ = √∑( $d_{i}$ - $\frac{}{d}$ )²/ n-1