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zhuklara [117]
2 years ago
15

What is the value of x will mark brain list  20 extra points

Mathematics
1 answer:
miskamm [114]2 years ago
4 0
Its an equilateral triangle so all sides are equal.

2x + 5 = 4x - 1
5 = 2x - 1
6 = 2x
3 = x

Do you get it?
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Sidana [21]
Answer is A. 1/3 !!!
8 0
2 years ago
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An object travels along a circular path so that it completes one revolution in 8 seconds. If the linear velocity of the object i
natima [27]

Answer:

Using the concept of speed-distance-time, we find that the diameter of the circular path is 12 inches.

Step-by-step explanation:

Given that the object completes one revolution in 8 seconds. So, the circular speed of the object is 2πr/8 = πr/4 inches per seconds, where r is the radius of the circular path. The speed can be written as:

πr/4 inches per seconds = 60πr/4 inches per minute = 15πr inches per minute.

But, it is given that the circular speed of the object is 90π inches per minute. So,

90π = 15πr

r = 6 inches

Since, diameter is the double of radius, d = 2r = 12 inches.

For more explanation, refer the following link:

brainly.com/question/17978382

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4 0
1 year ago
As an estimation we are told £3 is €4.<br> Convert £18 to euros.
Yuri [45]

Answer:

€24

Step-by-step explanation:

We can use ratios to solve this.

3:4 = 18:x

Cross multiply: 3x = 18*4

Divide: x = 18*4/3

Simplify: x = 6*4 = 24

5 0
1 year ago
Solve h(x) = 5 - 9x Find h(8)
Alex_Xolod [135]

h(x) = 5 - 9x

h(8) = 5 - 9×8 ( putting value x = 8)

h(8) = 5 - 72

h(8) = -67

Answer is -67.

4 0
3 years ago
Read 2 more answers
Interval is 0, 2pi) 4 sin^2x-4 sin x + 1 = 0
svetoff [14.1K]

Answer:

\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}}

Step-by-step explanation:

4\sin^2x-4\sin x+1=0\\\\2^2\sin^2x-2(2\sin x)(1)+1^2=0\\\\(2\sin x)^2-2(2\sin x)(1)+1^2=0\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(2\sin x-1)^2=0\iff2\ain x-1=0\qquad\text{add 1 to both sides}\\\\2\sin x=1\qquad\text{divide both sides by 2}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}

8 0
3 years ago
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