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Margaret [11]
3 years ago
13

The sum of two numbers is 80 . The ratio of those two numbers is 3:5 find the larger Number

Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0

Answer:

the larger number is 50

Step-by-step explanation:

Notice there are two unknown numbers. Let's address the smaller one as x and the larger one as y. now we can write two equations from translating the phrases given into algebraic expressions:

"the sum of two numbers is 80" can be written as:

x+y=80

Now the second phrase:

"The ratio of those two numbers is 3/5"

Notice here that in our ratio we need to use our small number (x) in the numerator of the quotient, and the larger number (y) in the denominator to make it in agreement with the small and larger numbers of the ratio \frac{3}{5}, and solve for x:

\frac{x}{y} = \frac{3}{5} \\x= \frac{3}{5}y

Replace the value of x we just obtained in the first equation we wrote, so we obtain one equation with only one unknown hat we should be able to solve:

x+y=80\\\frac{3}{5} y+y=80\\\frac{3}{5} y+\frac{5}{5} y=80\\\frac{8}{5}y=80 \\8y=80*5\\8y=400\\y=\frac{400}{8} \\y=50

Therefore the larger number (y) equals 50.

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Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR
erik [133]

Answer:

392

Step-by-step explanation:

Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.

Extend lines XQ, YR, YS and XP and mark their intersection as A and B.

Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore

  • all angles of the quadrilateral XAYB are right angles
  • all sides of XAYB are congruent and equal to 6 + 8 = 14 units.

Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,

XY^2=XA^2+AY^2\\ \\XY^2=14^2+14^2\\ \\XY^2=196+196\\ \\XY^2=392  

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Step-by-step explanation:

The computation of the volume of the cylinder is shown below:

As we know that

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From home, Mary’s work is two thirds along the way to training. Training is 2.5km from work. Mary normally goes to work, then tr
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First thing to do is to illustrate the problem, Since it was mentioned that work was along the way to training, the order is shown in the picture. Mary's home and workplace are nearer compared to her training center. It is also mentioned that the distance between work and home, denoted as x, is 2/3 of the total distance from home to training. The total distance is (x + 2.5). Thus,

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Thus, the distance from home to work is 5 km. This means that Mary has to walk this distance twice to return home to get her shoes. Then, she will travel again the total distance of 5+2.5 = 7.5 km to get to her training center. So,

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