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3 years ago

Together, a necklace and a bracelet cost $192. Find the price of each if the necklace costs 3 times as much as the bracelet

Mathematics

1 answer:

nata0808 [166]3 years ago

4 0

Answer:

the necklace costs $144 while the bracelet costs $48.

Step-by-step explanation:

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A puppy weighs534pounds.

Over [174]

The puppy weighs 92 oz

5 0

2 years ago

A drink is made from orange juice and lemonade in the ratio 3 : 7. How much lemonade is needed if 60 ml of orange juice is used?

lina2011 [118]

Answer:

140 ml

Step-by-step explanation:

60/3 = 20

20x7 = 140

8 0

2 years ago

Find the mean 35 40 12 16 25 10

ruslelena [56]

Answer: Mean = 23

Step-by-step explanation:

Given information:

35, 40, 12, 16, 25, 10

Given formula:

$Mean~=~\frac{Sum~of~terms}{Number~of~terms}$

Substitute values into the formula

$Mean~=~\frac{35~+~40~+~12~+~16~+~25~+~10}{6}$

Combine like terms

$Mean~=~\frac{75~+~28~+~35}{6}$

$Mean~=~\frac{103~+~35}{6}$

$Mean~=~\frac{138}{6}$

Simplify the fraction

$\Large\boxed{Mean=23}$

Hope this helps!! :)

Please let me know if you have any questions

4 0

2 years ago

What is the y value of the vertex of the function f(x)=-(x-3)(x+11)

AnnyKZ [126]

Answer:

Step-by-step explanation:

Because there is a minus sign infront of x-3, we can convert x-3 into the negative form:

- * x

- * -3

-x + 3

Which gives us:

(-x + 3)(x + 11)

Now expand the brackets with the formula:

(a + b)(c + d) = ac + ad + bc + bd

-x * x = -x²

-x * 11 = -11x

3 * x = 3x

3 * 11 = 33

-x² - 11x + 3x + 33

-x² - 8x + 33

The formula for finding the x coordinate of a vertex in a quadratic equation is:

x = $\frac{-b}{2a}$

Plug known variables in:

$x = \frac{-(-8)}{2(-1)}$

$x = \frac{8}{-2}$

$x = -4$

Now, to find the y coordinate, plug this variable back into the quadratic equation:

-x² - 8x + 33

$y = -(-4^2) - (32) + 33\\y = -16 + 32 + 33\\\\$

y = 49

So the y coordinate of the vertex is 49.

Hope this helps!

4 0

3 years ago

The goal of a nutritional study was to compare the caloric intake of adolescents living in rural areas of the US with the calori

stiks02 [169]

Answer:

To give more clarity to the question, lets examine the attached back-to-back stem plot.

Having examined the stem plot, we can using quick calculations, summarize that:

The mean (40.45 cal/kg) and median (41 cal/kg) daily caloric intake of ninth-grade students in the rural school is higher than the corresponding measures of center, mean (32.6 cal/kg) and median (32 cal/kg), for ninth-graders in the urban school.

The median and the mean for the students in the 9th grade in the urban school is lower than that of those of their contemporaries in the rural school. The respective medians and means are stated below:

Urban 9th Grade Students

Median = 32 cal/kg

Mean = 36 cal/kg

Rural 9th Grade Students

Median = 41 cal/kg

Mean = 41 cal/kg

Please note that all figures above have been approximated to the nearest whole number.

It is unreasonable to generalize the findings of this study to all rural and urban 9th-grade students in the United States because the sample is too small compared to the target population size.

To allow for generalization, they would have to collect and analyze more samples say from every state within America.

Cheers!

5 0

3 years ago