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marysya [2.9K]
3 years ago
7

Jaime's refrigerator loan statement said that he would pay $1,026 as interest after 4 years at an interest rate of 13.5%. How mu

ch did Jaime borrow to buy the refrigerator?
Mathematics
1 answer:
devlian [24]3 years ago
4 0

Answer:

$ 1900

Step-by-step explanation:

Starting from the equation of simple interest, which is defined as follows:

 I = P * r * t

Being I the interest, P the value of the product, r the interest rate and t would be time.

We want to know the price of the product, therefore, solving the equation we have:

P = I / r * t

We know each other's values so we replace:

 P = 1026 / (0.135 * 4)

P = $ 1900 was the value of the refrigerator Jaime bought.

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Here you go. Do you think that you could help me with my question

5a – 10b = 45 
5a – 10(3) = 45 
5a – 30 = 45 
+30 +30 
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<span>a = 15</span>
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The degree of a polynomial is the largest exponent on one of its variables (for a single variable), or the largest sum of exponents on variables in a single term (for multiple variables).

Step-by-step explanation:

ere, the term with the largest exponent is , so the degree of the whole polynomial is 6.

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Quadrilaterals ABCD and EFGH are similar. If the perimeter of the quadrilateral ABCD is equal to 4y² what is the perimeter of th
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Can't be determined.

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Sand pouring from a chute forms a conical pile whose height is always equal to the diameter. If the height increases at a consta
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Answer:

125\pi \frac{\text{ft}^3}{\text{min}}.

Step-by-step explanation:

Let x represent height of the cone.

We have been given that Sand pouring from a chute forms a conical pile whose height is always equal to the diameter.

We know that radius is half the diameter, so radius of cone would be \frac{x}{2}.

We will use volume of cone formula to solve our given problem.

V=\frac{1}{3}\pi r^2h

Upon substituting the value of height and radius in terms of x, we will get:

V=\frac{1}{3}\pi (\frac{x}{2})^2(x)

V=\frac{1}{3}\pi\frac{x^2}{4}(x)

V=\frac{1}{12}\pi x^3

Now, we will take the derivative of volume with respect to time as:

\frac{dV}{dt}=\frac{1}{12}\pi\cdot 3x^2\cdot \frac{dx}{dt}

\frac{dV}{dt}=\frac{1}{4}\pi\cdot x^2\cdot \frac{dx}{dt}

Upon substituting x=10 and \frac{dx}{dt}=5, we will get:

\frac{dV}{dt}=\frac{1}{4}\pi\cdot (10)^2\cdot 5

\frac{dV}{dt}=\frac{1}{4}\pi\cdot 100\cdot 5

\frac{dV}{dt}=\pi\cdot 25\cdot 5

\frac{dV}{dt}=125\pi

Therefore, the sand is pouring from the chute at a rate of 125\pi \frac{\text{ft}^3}{\text{min}}.

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