Answer:
yes
Step-by-step explanation:
and no
Use a Mohr circle to find the maximum shear stress relative to the axial stress.
Here we assume the axial stress is sigma, the transverse axial stress is zero.
So we have a Mohr circle with (0,0) and (0,sigma) as a diameter.
The centre of the circle is therefore (0,sigma/2), and the radius is sigma/2.
From the circle, we determine that the maximum stress is the maximum y-axis values, namely +/- sigma/2, at locations (sigma/2, sigma/2), and (sigma/2, -sigma/2).
Given that the maximum shear stress is 60 MPa, we have
sigma/2=60 MPa, or sigma=120 MPa.
(note: 1 MPa = 1N/mm^2)
Therefore
100 kN/(pi*d^2/4)=100,000 N/(pi*d^2/4)=120 MPa where d is in mm.
Solve for d
d=sqrt(100,000*4/(120*pi))
=32.5735 mm
Complement of an alngle means what you need to add to it to make 90 degrees
comlement of angle x is y such that x+y=90
so if complement of angle x is 25, that means the angle x is found by
x+25=90
minus 25 both sides
x=65 degrees
the angle measures 65 degree
Answer:
d.10
Step-by-step explanation:
Sample size is large enough if both n*p and n*(1 – p) are greater than or equal to 10.
Answer:
6x² (2x - 5)
Step-by-step explanation:
12x³ - 30x²
= 6x² (2x - 5)
