What is the value of ∣∣−89∣∣? A. −98 B. −89 C. 89 D. 98

A 3 foot tall globe standing next to a woman cast an 8 ft shadow. if the woman cats a shadow that is 16ft long , then how tall i

My name is Ann [436]

The woman is 6 foot tall

<h3>What is proportion?</h3>

Proportion can be defined as the mathematical comparison of two numbers.

These numbers could be numbers, elements, set or people

From the information given, we have that;

The globe is 3 feet and casts a shadow of 8ft
The woman cast a shadow of 16ft and is x feet tall

So,

if the globe is 3 foot tall and casts a shadow of 8ft

Then the woman is x foot tall to cast a shadow of 16ft

cross multiply

8x = 24

Make 'x' the subject

x = 48/ 8

x = 6 foot

Thus, the woman is 6 foot tall

Learn more about proportion here:

brainly.com/question/1781657

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3 0

2 years ago

A geometric sequence has an initial value of −8 and a common ratio of 1.5. Select all the function(s) or formula(s) that could r

Feliz [49]

Answer:

A and c

Step-by-step explanation:

I took the test

4 0

3 years ago

The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla

forsale [732]

Answer:

a)

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

b)

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

Step-by-step explanation:

The formula is:

$v=\frac{2 \pi R}{T}$

Where

v is speed

R is radius

T is time

and another formula for centripetal acceleration:

$a_c=\frac{4 \pi^{2} R}{T^2}$

Now,

a)

at equator, the radius is radius of earth (given), time in seconds is

T = 24 * 60 * 60 = 86,400

THus,

$v_E=\frac{2 \pi (6.38*10^{6}}{86,400}=463.97$

Speed at Equator = 463.97 meters per second

Centripetal Acceleration:

$a_{cE}=\frac{v_E^2}{R_E}=\frac{463.97}{6.38*10^{6}}=3.37*10^{-2}$

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

b)

At 30.0° north of the equator:

$R_N=R_E Cos (30)= (6.38*10^6)Cos(30)=5.53*10^6$

Now,

Speed = $v_{30N}=\frac{2 \pi (5.53*10^6)}{86,400}=401.79$

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

$a_{30N}=\frac{v_E^2}{R_E}=\frac{401.79}{5.53*10^6}=2.92*10^{-2}$

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

4 0

3 years ago

Write in Slope-Intercept Form the equation of the line that has the given slope and point. 5 p (4, - 2), m = 1 /4

Ainat [17]

Answer:

y = 1/4x - 3

Step-by-step explanation:

y + 2 = 1/4(x - 4)

y = 1/4x - 3

5 0

3 years ago

Jervane is planning on buying a coffee and several donuts for a road trip. She wants to spend no more than $20 in total. Coffee

max2010maxim [7]

Answer:

8

Step-by-step explanation:

Given:

Total money Jervane can spend = $20.

Cost of a coffee = $3.

Cost of a donut = $2.

To find: Maximum number of donuts Jervane can buy.

Solution:

Let the number of donuts she can buy be $x$ .

She wants to spend no more than $20 in total.

So,

$3+2x\leq 20$

$\Rightarrow 2x\leqslant 20-3$

$\Rightarrow 2x\leqslant 17$

$\Rightarrow x\leqslant \frac{17}{2}$

$\Rightarrow x\leqslant 8 \frac{1}{2}$

As the number of donuts can only be a natural number.

Hence, the maximum number of donuts that Jervane can buy are 8.

8 0

3 years ago